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vivado [14]
3 years ago
6

The graph represents a quadratic function. Write the function in vertex form.

Mathematics
1 answer:
Luba_88 [7]3 years ago
8 0

Answer:

y=3(x+3)^2-8

Step-by-step explanation:

Vertex form:

y=a(x-h)^2+k

h=-3, k=-8

y=a(x+3)^2-8

sub (-4,-5)

-5=a(-4+3)^2-8

a=3

y=3(x+3)^2-8

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Answer:

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Step-by-step explanation:

Perhaps you want to use the points (t, P) = (4, 150) and (6, 160) to find the parameters P0 and k in the equation ...

  P(t)=P_0\cdot e^{kt}

We know from the given points that we can write the equation as ...

  P(t)=150\left(\dfrac{160}{150}\right)^{(t-4)/(6-4)}=150\left(\dfrac{16}{15}\right)^{\frac{t}{2}-2}\\\\=150\left(\dfrac{16}{15}\right)^{-2}\times\left(\left(\dfrac{16}{15}\right)^{\frac{1}{2}}\right)^t

Comparing this to the desired form, we see that ...

  P_0=150\left(\dfrac{16}{15}\right)^{-2}\approx 131.836\\\\e^{k}=\left(\dfrac{16}{15}\right)^{1/2}\rightarrow k=\dfrac{1}{2}(\ln{16}-\ln{15})\approx 0.0322693

So, the approximate equation for P is ...

  P(t)=131.836\cdote^{0.032t}

And the parameters of interest are ...

  • k = 0.032
  • P0 = 131.836
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