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Schach [20]
3 years ago
11

Cheese pizzas cost $7 and pepperoni pizzas cost $9. You order a total of 40 pizzas and the bill is $310. How many of each pizza

did you order
Mathematics
1 answer:
Anon25 [30]3 years ago
8 0

Answer: cheese pizzas = 25 , Pepperoni pizzas = 15

Step-by-step explanation:

Let x = Number of cheese pizzas, y =  Number of pepperoni pizzas.

As per given,

x+y=40\ \ \ (i)\\\\ 7x+9y=310\ \ \ (ii)

Multiply 7 on both sides of (i), we get

7x+7y=280\ \ \ (iii)

Eliminate (iii) from (ii), we get

2y= 30\\\\\Rightarrow\ y=15

Put value of y in (i) ,  x+15=40\Rightarrow\ x= 40-15= 25

Hence, cheese pizzas = 25 , Pepperoni pizzas = 15

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16ax + 4x^2 +16a^2 HELP!!!!!!
butalik [34]

Answer:

  • (2x + 4a)²

Step-by-step explanation:

Assumed it is asking to factorize

Used formula:

m² +2mn + n² = (m + n)²

  • 16ax + 4x^2 +16a^2 =
  • (2x)² +2*4x*2a + (4a)² =
  • (2x + 4a)²
3 0
3 years ago
Read 2 more answers
PLZ DO EXACTLY AS STATED, WILL GIVE BRAILIEST AND 30 POINTS!!
dsp73

Answer:

bro just did this on a TGA

Step-by-step explanation:

A. no solutions and a contradiction

B. infinate solutions and an identity

C. one solution and niether

3 0
3 years ago
(solve the following problem using integers. show ALL your work.)
yulyashka [42]

Answer:

$4

Step-by-step explanation:

30+20=50

50-48=2

2+20+=22

22-18=4

if she has 30 then gets 20 she has 50. Then she spends 48 dollars leaving her with only 2 dollars. She then makes another 20 dollars so she now has 22 dollars. She spends 18 dollars leaving her with 4 dollars.

8 0
3 years ago
Suppose that a random sample of 10 adults has a mean score of 62 on a standardized personality test, with a standard deviation o
aniked [119]

Answer:

The 90% confidence interval for the mean score of all takers of this test is between 59.92 and 64.08. The lower end is 59.92, and the upper end is 64.08.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.9}{2} = 0.05

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.05 = 0.95, so z = 1.645

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 1.645*\frac{4}{\sqrt{10}} = 2.08

The lower end of the interval is the sample mean subtracted by M. So it is 62 - 2.08 = 59.92

The upper end of the interval is the sample mean added to M. So it is 62 + 2.08 = 64.08.

The 90% confidence interval for the mean score of all takers of this test is between 59.92 and 64.08. The lower end is 59.92, and the upper end is 64.08.

5 0
3 years ago
Helppppppppopopoppppp
skelet666 [1.2K]

Answer:

DG = 30

Step-by-step explanation:

Given:

DH = 6

DE = 4

EF = 16

Required:

DG

Solution:

DG = DH + HG

DG = 6 + HG

Let's find HG

Given that HE is parallel to the third side of ∆DGF, based on the side-splitter theorem, the other two sides of ∆DGF are divided proportionally.

Therefore,

DH/HG = DE/EF

6/HG = 4/16

Cross multiply

HG*4 = 16*6

HG = 96/4

HG = 24

✔️DG = 6 + HG

DG = 6 + 24

DG = 30

7 0
3 years ago
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