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Naily [24]
3 years ago
15

Suppose that some company has just sent your company a huge list of customers. You respond to that company with a strongly worde

d note because you only wanted the phone number of one customer, Mike Smith. They, in turn, reply to you suggesting that you simply find him quickly using binary search. Explain why it might not, in fact, be possible to use binary search on the huge list.
Computers and Technology
1 answer:
Leto [7]3 years ago
5 0

Answer:

Explanation:

Actually this is possible

First sort the list of all names in ascending order based on string comparison (ASCII value)

The middle can be found as we have total number of contacts

Binary search can be applied by comparing the name string

If any of these is not given or time bound then binary search can not be applied.

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sasho [114]

Using the computational language in python it is possible to write a code that we will use graphics to organize the names of the directors and the films they made.

<h3>Writing code in python:</h3>

<em>import pandas as pd</em>

<em>df = pd.read_csv('all_data/movie_metadata.csv')</em>

<em>print('Shape: ',df.shape)</em>

<em>df.head()</em>

<em>name = df[['director_name','imdb_score']] </em>

<em>directors = name.groupby(['director_name']).mean() </em>

<em>directors = directors.reset_index() </em>

<em>directors = directors.stack()</em>

<em>print(directors,'\n')</em>

<em>print(type(directors),'\n')</em>

<em>print(directors[directors=='Steven Spielberg'],'\n')</em>

<em>print(directors[102]['imdb_score'])</em>

<em>miyazaki = df[df['director_name'] == 'Hayao Miyazaki']['movie_title']</em>

<em>print(miyazaki)</em>

<em>pivot_agg = pd.pivot_table(df,values='imdb_score', index=['country'], columns=['director_name'],aggfunc=np.median)</em>

<em>pivot_agg</em>

<em>gladiator_duration = df[df['movie_title']=='Gladiator\xa0']['duration'] </em>

<em>gladiator_duration</em>

See more about python at brainly.com/question/18502436

#SPJ1

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2 years ago
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