If you eliminate obvious wrong answers you increase your chances of getting the question correct.
Notice the inequality signs are both "equal to" which means a solid boundary line. This means choice B and D can not be correct.
You can test a point that is exclusively in the shaded region of each graph.
x + 2y ≤ 4
-x -x solve for y by moving x term
2y ≤ -x + 4
÷2 ÷2 divide both sides of the inequality by 2
y ≤ -1/2x + 2 ← plot 2 on y-axis then move down 1 and right 2 put 2nd point
shade below the solid line
3x - y ≥ 2 when solved for y → y ≤ 3x - 2 (the inequality sign switched because in the process of solving for y I had to divide by a negative number)
plot -2 on the y-axis then move up 3 and to the right 1 put 2nd point
shade below the line
the answer is choice A only graph where they have shaded below both lines...use the y-intercept as a guide for shading above or below the line... shading where numbers are greater than the y-intercept is shading above the line and shading where numbers are less then the y-intercept is shading below the line
Answer:
Step-by-step explanation:
You set both sides equal to 180
4x + 20 + 84 = 180
4x = 76
x= 19
A The product of an even number and an even number
Answer:
-1, 4+i, 4-i
Step-by-step explanation:
x^4- 6x^3 + 2x^2 + 26x + 17
Using the rational root theorem
we see if 1, -1, -17 or 17 are roots
Check and see if 1 is a root
1^4- 6(1^3) + 2(1^2) + 26(1) + 17=0
1-6+2+26+17 does not equal 0 1 is not a root
-1
1^4- 6(-1^3) + 2(1^2) + 26(-1) + 17=0
1 +6 +2 -26+17 = 0
-1 is a root
Factor out (x+1)
(x+1) ( x^3-7x^2+9x+17)
Using the rational root theorem again on x^3-7x^2+9x+17
Checking -1
-1 -7 -9 +17=0
-1 is a root
(x+1) (x+1) (x^2-8x+17)
Using the quadratic on the last
8 ±sqrt(8^2 - 4(1)17)
--------------------------------
2
gives imaginary roots
4±i
