Answer:
m≥3
Step-by-step explanation:
This is a problem in "binomial probability." Either the archer hits his target or he does not. This experiment is performed 5 times (so that n=5), and the probability that the archer will hit the target is 0.7 (so that p=0.7).
We need to find the binomial probability that x=3 when the possible outcomes are {0, 1, 2, 3, 4, 5}.
You could use a table of binomial probabilities to evaluate the following:
P(5, 0.7, 3).
Alternatively, you could use a TI-83 or TI-84 calculator and its built-in "binompdf( " function.
I evaluated binompdf(5,0.7,3) and obtained the result 0.309.
Answer:
the quotient is 6x^2 - 16x + 16, and the remainder is just 4
Step-by-step explanation:
The polynomial 6x^3-10x^2+20 has coefficients {6, -10, 0, 20}. Division by the binomial x + 1 requires that we use -1 as the divisor. The synthetic division setup becomes:
-1 / 6 -10 0 20
-6 16 -16
-----------------------------
6 -16 16 4
Taking the coefficients {6, -16, 16}, we write the quotient as
6x^2 - 16x + 16, and the remainder as just 4.
Answer:
From given relation the value of β is 37.5°
Step-by-step explanation:
Given as :
α and β are two acute angles of right triangle
Acute angle have measure less than 90°
Now given as :
= 
Or, 
=
SO, 
= 
Or, 90° = + 
or, 90° = 
+ 4x
Or, 90° = 
So, x = 
= 15°
∴ = 
So, = sin
∴ The value of Ф_1 = = 37.5°
Similarly = 
So ,The value of Ф_2 = 
= 52.5°
∵ β 
α
So, As 37.5°52.5°
∴ β = 37.5°
Hence From given relation the value of β is 37.5° Answer
