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2 years ago

6

Diameter of a cylindrical tank is 9 feet and the height of a tank is 25 feet. Find the volume of the cylindrical tank to the nea

rest hundredth place.

1 answer:

Anna11 [10]2 years ago

5 0

Answer:

write a story or description in your society caused by extremity

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Is x=3 a solution for the equation: 3x + 7 = 13<br> Why or why not ?

expeople1 [14]

Answer:

No.

Step-by-step explanation:

There are two different ways to do this - solve for x in the given equation or substitute the value for x and see if you get a true statement.

3x + 7 = 13 subtract 7 from both sides

3x = 6 divide by 3 on both sides

x = 2

3(3) + 7 = 13

9 + 7 = 13

16 ≠ 13

Therefore, x = 3 is not a solution for 3x + 7 = 13.

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2 years ago

Hi i was wondering if you can help me with this 4x+8<4(x-9) please help me solve this and help me show the work I don’t remem

slava [35]

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nope I do not know what to do

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2 years ago

Which of the following are always true in a logical system? Check all that

mr Goodwill [35]

Answer:

A. Theorems

and

B.Corollaries

Step-by-step explanation:

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3 years ago

Read 2 more answers

Matt is running the family fun fair at school.He collected about $65 in donations each month for the 7 months he was planning th

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You do 7 x 65 dddddtghj

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2 years ago

Please help me with the question

mars1129 [50]

(i) The mean is

$\displaystyle E(X) = \sum_x x \, P(X = x) \\\\ E(X) = 1\cdot0.175 + 2\cdot0.315 + 3\cdot0.211 + 4\cdot0.092 + 5\cdot0.207 \\\\ \boxed{E(X) = 2.839}$

The variance is

$V(X) = E((X - E(X))^2) = E(X^2) - E(X)^2$

Compute the second moment $E(X^2)$ :

$\displaystyle E(X^2) = \sum_x x^2 \, P(X = x) \\\\ E(X) = 1^2\cdot0.175 + 2^2\cdot0.315 + 3^2\times0.211 + 4^2\times0.092 + 5^2\times0.207 \\\\ E(X^2) = 9.997$

Then the variance is

$\boxed{V(X) \approx 1.9171}$

(ii) For a random variable $Z=aX+b$ , where $a,b$ are constants, we have

$E(Z) = E(aX+b) = E(aX) + E(b) = a E(X) + b$

and

$V(Z) = E((aX+b)^2) - E(aX+b)^2 \\\\ V(Z) = E(a^2 X^2 + 2ab X + b^2) - (a E(X) + b)^2 \\\\ V(Z) = a^2 (E(X^2) - E(X)^2) \\\\ V(Z) = a^2 V(X)$

Then for $Y=\frac{X+3}2$ , we have

$E(Y) = \dfrac12 E(X) + \dfrac32 \\\\ \boxed{E(Y) = 2.918}$

$E(Y^2) = E\left(\left(\dfrac{X+3}2\right)^2\right) = \dfrac14 E(X^2) + \dfrac32 E(X) + \dfrac94 \\\\ \boxed{E(Y^2) \approx 9.0028}$

3 0

2 years ago