30% diet and 10 regular not shoreee
A acute angle is always less than 90 degrees. So the answer is A.
Answer:
t≈8.0927
Step-by-step explanation:
h(t) = -16t^2 + 128t +12
We want to find when h(t) is zero ( or when it hits the ground)
0 = -16t^2 + 128t +12
Completing the square
Subtract 12 from each side
-12 = -16t^2 + 128t
Divide each side by -16
-12/-16 = -16/-16t^2 + 128/-16t
3/4 = t^2 -8t
Take the coefficient of t and divide it by 8
-8/2 = -4
Then square it
(-4) ^2 = 16
Add 16 to each side
16+3/4 = t^2 -8t+16
64/4 + 3/4= (t-4)^2
67/4 = (t-4)^2
Take the square root of each side
±sqrt(67/4) =sqrt( (t-4)^2)
±1/2sqrt(67) = (t-4)
Add 4 to each side
4 ±1/2sqrt(67) = t
The approximate values for t are
t≈-0.092676
t≈8.0927
The first is before the rocket is launched so the only valid answer is the second one
Answer:15
Step-by-step explanation:
You have to divide the fractions so it 3/4÷1/10 then you can do keep change flip so the new equation is 3/4×10/1 or 3/4×10 then cross simply then get 3/2×5/1 to get 15/2 then use division to get 7 1/2
No, while the difference represents the absolute magnitude of two numbers . . . for example . . .
The difference between 5 and 2 is . . . 3
The difference between 6.4 and 9.5 is . . . 3.1
. . . there is still the chance that the difference may be zero . . . in which case the difference is neither positive nor negative
. . . so in short . . . the answer is . . . <span>NO</span>
