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3 years ago

Simplify the expressionn ( p l e a s e )

Mathematics

1 answer:

JulsSmile [24]3 years ago

8 0

Use Photomath just take the picture of the question and it gives you the answer

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Please help need answer for both questions

myrzilka [38]

Answer:

1. 32, 12

2. Enlargement

Step-by-step explanation:

Enlarged by a scale factor of 4

(Multiply all points by 4)

8 x 4 = 32

3 x 4 = 12

It is an enlargement because the points are larger than before.

5 0

3 years ago

Find X. Show work please

rodikova [14]

5x +12 = 6x - 10
Move the 5x over to the right by subtraction
12 = x - 10
Then move the 10 to the left by addition
22 = x

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3 years ago

LOOK AT PICTURE, WHOEVER HAS CORRECT ANSWER, I WILL MARK BRAINIEST :)

Sauron [17]

Answer:

Step-by-step explanation:

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3 years ago

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ki77a [65]

Honestly I don’t know but I think it’s d

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4 years ago

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A study is conducted to determine if a newly designed text book is more helpful to learning the material than the old edition. T

CaHeK987 [17]

Answer:

We need to conduct a hypothesis in order to check if the mean is higher than 75, the system of hypothesis are :

Null hypothesis: $\mu \leq 75$

Alternative hypothesis: $\mu > 75$

A. One-Tailed

$z=\frac{82.2-75}{\frac{10.4}{\sqrt{10}}}=2.189$

$p_v =P(z>2.189)=0.0143$

If we compare the p value and the significance level given $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis.

Step-by-step explanation:

Data given and notation

We have the following data: 84 94 80 88 77 68 90 74 96 71

We can calculate the sample mean with the following formula:

$\bar X =\frac{\sum_{i=1}^n X_i}{n}$

And replacing we got:

$\bar X=82.2$ represent the sample mean

$\sigma=10.4$ represent the population standard deviation

$n=10$ sample size

$\mu_o =75$ represent the value that we want to test

$\alpha=0.01$ represent the significance level for the hypothesis test.

z would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is higher than 75, the system of hypothesis are :

Null hypothesis: $\mu \leq 75$

Alternative hypothesis: $\mu > 75$

A. One-Tailed

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$z=\frac{82.2-75}{\frac{10.4}{\sqrt{10}}}=2.189$

P-value

Since is a ONE-TAILED test the p value would given by:

$p_v =P(z>2.189)=0.0143$

Conclusion

If we compare the p value and the significance level given $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis.

5 0

3 years ago