PLEASE HELP MEEE AND DONT GIVE A FAKE ANSWERRRR

Mathematics

2 answers:

Elodia [21]3 years ago

5 0

Answer:

dang feel bad for taking the 44 points but thats your problem have a nice day

Step-by-step explanation:

Alex Ar [27]3 years ago

3 0

Answer: Mount Everest: 8,849.87 meters, Mount Olympus: 2,919.07 meters

Step-by-step explanation: Part A: 5900 Part B: 5930.8 Part C: It's reasonable because part a's answer and part b's answer is pretty accurate and close enough to each other, so yes it is reasonable. But the estimate is very reasonable.

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1) Order the animals by sleep time from least to greatest.

Zolol [24]

The way to line the animals is to put them in order going down. 0.433 56.3% 19/40 65.8%. Then you try to figure out what you need to convert so that you can get your answer. 56.3% changes to 0.563 because you move the decimal two places to the left. 65.8% changes to 0.658 and 19/40 is 0.475. 0.433 0.563 0.475 0.658. Now you compare each row to figure them out. When you do that your answer will be 0.433, 0.475, 0.563, and 0.658. I sleep about 9/24 of the day which is 0.375 and I will fit right befor 0.433.

4 0

3 years ago

The decreasing population, p, of owls in a national park is being monitored by ecologists and is modeled by the equation p=−0.

n200080 [17]

By solving a quadratic equation, it can be verified that

The owl population will disappear after 329.12 years

What is a quadratic equation?

At first it is important to know about equation

Equation shows the equality between two algebraic expressions by connecting the two algebraic expressions by an equal to sign.

A two degree equation is known as quadratic equation.

Here, a quadratic equation needs to be solved

The decreasing population, p, of owls in a national park is being monitored by ecologists and is modeled by the equation p= $-0. 4t^2+128t+1,200$

For population to disappear, p =0

$-0. 4t^2+128t+1,200 = 0\\0.4t^2 -128t - 1200 = 0\\4t^2 - 1280t - 12000 = 0\\4(t^2 - 320 t - 3000) = 0\\t^2 - 320t -3000 = 0\\t = \frac{-(-320)\pm \sqrt{(-320)^2 - 4 \times 1 \times (-3000)}}{2 \times 1}\\t = \frac{320 \pm 338.23}{2}\\t = \frac{320 + 338.23}{2} \ or \ t = \frac{320 - 338.23}{2}\\t = 329.115 \ or \ t = -9.115$