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kondor19780726 [428]

3 years ago

15

What is 32 ÷ 6 step by step solution

1 answer:

weeeeeb [17]3 years ago

8 0

You do 5 times 6 which equals 30 and you get left with a remainder of 2.
Answer: 5 with a remainder of 2.

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yan [13]

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3 years ago

Solve the inequality for x: 25 - 14x < 53*

Mamont248 [21]

Answer:

x must be greater than -53/14

(im not 100% sure but i think this is correct)

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4 years ago

Dalton takes a rectangular piece of fabric and cuts from one corner to the opposite corner. If the piece of fabric is 12 centime

Gemiola [76]

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4 years ago

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Makovka662 [10]

Let $u=x^2-4$ and $v=4x-5$ . By the product rule,

$\dfrac{\mathrm d(u^5v^4)}{\mathrm dx}=\dfrac{\mathrm d(u^5)}{\mathrm dx}v^4+u^5\dfrac{\mathrm d(v^4)}{\mathrm dx}$

By the power rule, we have $(u^5)'=5u^4$ and $(v^4)'=4v^3$ , but $u,v$ are functions of $x$ , so we also need to apply the chain rule:

$\dfrac{\mathrm d(u^5)}{\mathrm dx}=5u^4\dfrac{\mathrm du}{\mathrm dx}$

$\dfrac{\mathrm d(v^4)}{\mathrm dx}=4v^3\dfrac{\mathrm dv}{\mathrm dx}$

and we have

$\dfrac{\mathrm du}{\mathrm dx}=2x$

$\dfrac{\mathrm dv}{\mathrm dx}=4$

So we end up with

$\dfrac{\mathrm d(u^5v^4)}{\mathrm dx}=10xu^4v^4+16u^5v^3$

Replace $u,v$ to get everything in terms of $x$ :

$\dfrac{\mathrm d((x^2-4)^5(4x-5)^4)}{\mathrm dx}=10x(x^2-4)^4(4x-5)^4+16(x^2-4)^5(4x-5)^3$

We can simplify this by factoring:

$10x(x^2-4)^4(4x-5)^4+16(x^2-4)^5(4x-5)^3=2(x^2-4)^4(4x-5)^3\bigg(5x(4x-5)+8(x^2-4)\bigg)$

$=2(x^2-4)^4(4x-5)^3(28x^2-57)$

7 0

3 years ago

Which is the midpoint of the segment joining (12, 2) and (-5, – 7)?

Rainbow [258]

Answer:

$m(x, y)=(\frac{7}{2} , -\frac{5}{2} )$

Step-by-step explanation:

Midpoint of line segment is calculated as

$m(x, y)=(\frac{x_1+x_2}{2} , \frac{y_1+y_2}{2} )$ -----------(1)

Here

$(x_1, y_1) = (12,2) \ \ and \ \ (x_2, y_2) = (-5, -7)$

Substituting values in equation (1)

$m(x, y)=(\frac{12-5}{2} , \frac{2-7}{2} )$

$m(x, y)=(\frac{7}{2} , -\frac{5}{2} )$

3 0

3 years ago