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zlopas [31]
3 years ago
15

Which street is parallel to 1st Ave?

Mathematics
1 answer:
mestny [16]3 years ago
6 0

Answer:

i believe its the second ave

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How to solve this system of equal: x+y+z=1;x^2+y^2+z^2=1
swat32

There are infinitely many solutions.

Algebraically, we can eliminate z and try to solve for x,y:

x+y+z=1\implies z=1-x-y

Then

x^2+y^2+(1-x-y)^2=1

\implies x^2+y^2+1-2x+x^2-2y+y^2+2xy=1

\implies x^2-x+y^2-y+xy=0

which is the equation of an ellipse.

5 0
4 years ago
Subtract 7x+3 from 2x-7
AysviL [449]

Subtract 7x+3 from 2x-7

(2x - 7) - (7x + 3) =

2x - 7 - 7x + 3

-5x -4

6 0
3 years ago
The graph shows which equation?
GalinKa [24]

it isn't the first 2 options

I'd say it's y=1/2x - 2

6 0
2 years ago
What is the value (total) of 14+10+(-14)
Dima020 [189]

Answer:

10

Step-by-step explanation:

14+10=24-14=10

8 0
3 years ago
Read 2 more answers
Suppose that prices of recently sold homes in one neighborhood have a mean of $215,000 with a standard deviation of $8900. Using
bonufazy [111]

Answer:

The minimum percentage of recently sold homes with prices between $197,200 and $232,800 is 75%.

Step-by-step explanation:

Chebyshev Theorem

The Chebyshev Theorem can also be applied to non-normal distribution. It states that:

At least 75% of the measures are within 2 standard deviations of the mean.

At least 89% of the measures are within 3 standard deviations of the mean.

An in general terms, the percentage of measures within k standard deviations of the mean is given by 100(1 - \frac{1}{k^{2}}).

In this question:

Mean of $215,000, standard deviation of $8900.

What is the minimum percentage of recently sold homes with prices between $197,200 and $232,800?

215000 - 2*8900 = 197200

215000 + 2*8900 = 232800

Within 2 standard deviations of the mean, so:

The minimum percentage of recently sold homes with prices between $197,200 and $232,800 is 75%.

4 0
3 years ago
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