Answer:
<h2>$66</h2>
Step-by-step explanation:
Step one:
given data
charges
$4 per bag
$10 weekly fee
let the number of bag be x
and let the total charges be y
<em>the linear function for the total per week is</em>
<em>y=4x+10</em>
Step two:
the independent variable is the weekly fee of $10
for x=14
y=4(14)+10
y=56+10
y=$66
The arithmetic formula is expressed as an = a1 + d *(n-1)where n is an integer. Substituting from the given a1 = -12 and a27 = 66, 66 = -12 + d *(27-1). hence , d is equal to 3. a42 thus using the formula is equal to 111. The final answer to this problem is 111.
[~Answer~] (4.):
<em>Hello there! I'm Avery, and I'm here to help you! I mostly believe the answer </em><em>is 1 2/3
+++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++</em>
[~Answer Explanation~]:
First:
Convert any mixed numbers to fractions.
Reduce fractions where possible.
Then your initial equation becomes:
356÷72
Applying the fractions formula for division,
=35×26×7
=70/42
Simplifying 70/42, the answer is
=1 2/3
+++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++
[~Last Messages~]:
Okay, I really hope my answer is correct.
I am truly sorry if it's wrong :(
Have a great morning, afternoon, or night. <333
[-!AveryIsSomeHowAlive!-]
A.) For the Junior Varsity Team, mean would be the appropriate measure of center since the data is <span>symmetric or well-proportioned while we should use standard deviation for getting the measure of spread since it also measures the center and how far the values are from the mean.
b.) For the Varsity Team, the median would be the appropriate measure of the center since the data is skewed left and not evenly distributed so median could be used since it does not account for outliers while we use IQR or interquartile range in measuring the spread of data since IQR does not account for the data that is skewed. </span>
What kind of operation is this ? it just says x and a nine.
