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OlgaM077 [116]
3 years ago
11

Zoom in to see more clear :)

Mathematics
1 answer:
algol133 years ago
5 0

Answer:

1) x=30 degrees

2)y=20 degrees

1) 3x+2x+1x= 6x (a triangle is normally 180 degrees) 180 divide 6=30 (this is because 6 Xs make up the triangle)

2) 2y+5y+5+y+15= 8y+20, (since a triangle has 180 degrees) 8y+20=180 (-20 from both sides) 8y=160, 160 divide 8=20

(I hope this makes sense)

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X-(-6)=-2 EXPLAIN YOUR ANSWER
Zielflug [23.3K]

Answer:

If your asking for the Value of X the answer would be (-8)

Step-by-step explanation:

when your subtracting a negative, it's the same as addition, and if the equation should be equal to 2, then the answer would be (-8), because

(-8) - (-6) = -2.

8 0
3 years ago
a local park is shaped like a square with sides 6 meters long. A circular splash fountain is being placed in the middle of the p
DENIUS [597]

Answer: 624 Square meters

Step-by-step explanation:

6 0
3 years ago
Birds arrive at a birdfeeder according to a Poisson process at a rate of six per hour.
m_a_m_a [10]

Answer:

a) time=10 \frac{1}{6}=\frac{10}{6}=1.67 hours

b) P(T\geq 0.25h)=e^{-(6)0.25}=0.22313

c) P(T\leq 0.0833)=1-e^{-(6)0.0833}=0.39347

Step-by-step explanation:

Definitions and concepts

The Poisson process is useful when we want to analyze the probability of ocurrence of an event in a time specified. The probability distribution for a random variable X following the Poisson distribution is given by:

P(X=x) =\lambda^x \frac{e^{-\lambda}}{x!}

And the parameter \lambda represent the average ocurrence rate per unit of time.

The exponential distribution is useful when we want to describ the waiting time between Poisson occurrences. If we assume that the random variable T represent the waiting time btween two consecutive event, we can define the probability that 0 events occurs between the start and a time t, like this:

P(T>t)= e^{-\lambda t}

a. What is the expected time you would have to wait to see ten birds arrive?

The original rate for the Poisson process is given by the problem "rate of six per hour" and on this case since we want the expected waiting time for 10 birds we have this:

time=10 \frac{1}{6}=\frac{10}{6}=1.67 hours

b. What is the probability that the elapsed time between the second and third birds exceeds fifteen minutes?

Assuming that the time between the arrival of two birds consecutive follows th exponential distribution and we need that this time exceeds fifteen minutes. If we convert the 15 minutes to hours we have 15(1/60)=0.25 hours. And we want to find this probability:

P(T\geq 0.25h)

And we can use the result obtained from the definitions and we have this:

P(T\geq 0.25h)=e^{-(6)0.25}=0.22313

c. If you have already waited five minutes for the first bird to arrive, what is the probability that the bird will arrive within the next five minutes?

First we need to convert the 5 minutes to hours and we got 5(1/60)=0.0833h. And on this case we want a conditional probability. And for this case is good to remember the "Markovian property of the Exponential distribution", given by :

P(T \leq a +t |T>t)=P(T\leq a)

Since we have a waiting time for the first bird of 5 min = 0.0833h and we want that the next bird will arrive within 5 minutes=0.0833h, we can express on this way the probability of interest:

P(T\leq 0.0833+0.0833| T>0.0833)

P(T\leq 0.1667| T>0.0833)

And using the Markovian property we have this:

P(T\leq 0.0833)=1-e^{-(6)0.0833}=0.39347

3 0
3 years ago
Choose all that give the correct expression for the quantity described. The difference of nine times a number x and the quotient
ohaa [14]

Step-by-step explanation:

We are to get the expression for the following statements;

1) The difference of nine times a number x and the quotient of that number and 5.

The product of nine and a number x is expressed as;

=9 \times x\\= 9x

The quotient of that number and 5.

= \frac{x}{5}

The difference between both expression;

9x - \frac{x}{5}

Hence, the difference of nine times a number x and the quotient of that number and 5 is expressed as 9x - \frac{x}{5}

2) Eight more than the quotient of twelve and a number n

Quotient of twelve and a number n is expressed as:

\frac{n}{12}

Eight more than the resulting function is;

\frac{n}{12}+8

Hence eight more than the quotient of twelve and a number n is expressed as \frac{n}{12}+8

3) The product of a number and the quantity 'six minus the number' plus the quotient of eight and the number.

Let the number be x:

six minus the number is expressed as;

6-x

product of a number x and the quantity 'six minus the number is;

x(6-x)

quotient of eight and the number is;

\frac{8}{x}

Taking the resulting sum of the last two expression

x(6-x) + 8x

Hence the product of a number and the quantity 'six minus the number' plus the quotient of eight and the number is expressed as;

x(6-x) + 8x

4) Sum of three consecutive even integers. 2x + (2x + 2) + (2x + 4).

Let the first even number be 2x

The consecutive even numbers are gotten by adding 2 to the preceding number. The two consecutive even integers are 2x+2 and 2x+2+2

the sum of three consecutive even integers is expressed as;

= 2x +(2x+2)+(2x+2+2)\\=  2x+(2x+2)+(2x+4)

4 0
3 years ago
Can someone please answer this for me i cant figure it out.
Jlenok [28]
<h3>Answer:</h3>

\displaystyle x^{\frac{2}{3}}

<h3>Step-by-step explanation:</h3>

The rules of exponents tell you ...

... (a^b)(a^c) = a^(b+c) . . . . . . applies inside parentheses

... (a^b)^c = a^(b·c) . . . . . . . . applies to the overall expression

The Order of Operations tells you to evaluate inside parentheses first. Doing that, you have ...

... x^(4/3)·x^(2/3) = x^((4+2)/3) = x^2

Now, you have ...

... (x^2)^(1/3)

and the rule of exponents tells you to multiply the exponents.

... = x^(2·1/3) = x^(2/3)

3 0
3 years ago
Read 2 more answers
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