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ad-work [718]
3 years ago
10

( • )( • )ԅ(‾⌣‾ԅ)( • )( • )ԅ(‾⌣‾ԅ)( • )( • )ԅ(‾⌣‾ԅ)

Mathematics
1 answer:
Montano1993 [528]3 years ago
4 0
BEHJEJEBEHRUUE what is this eheujrf
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A number,y,is 2 more than 3 times another number,x, the sum of the 2 numbers is 26. What are the two numbers?
Ivanshal [37]
Y = 2 + 3x
x + y = 26

Substitute:
x + (2 + 3x) = 26
4x + 2 = 26
4x = 24
x = 6

6 + y = 26
y = 20
3 0
3 years ago
Find the exact values of sin A and cos A. Write fractions in lowest terms. A right triangle ABC is shown. Leg AC has length 21,
andrey2020 [161]
SinA=BC/AB=28/35=4/5; cosA=AC/AB=21/35=3/5.
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3 years ago
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What kind of property is this −2.2+(−3.7+(−1.4))=(−2.2+(−3.7))+(−1.4) A. associative property B. communicative property C. oppos
MissTica
The associative property states : a + (b + c) = (a + b) + c....and this is what ur problem is.
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3 years ago
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When studying radioactive material, a nuclear engineer found that over 365 days,
Gnom [1K]

Answer:

a) The mean number of radioactive atoms that decay per day is 81.485.

b) 0% probability that on a given day, 50 radioactive atoms decayed.

Step-by-step explanation:

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\lambda}*\lambda^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\lambda is the mean in the given interval.

a. Find the mean number of radioactive atoms that decayed in a day.

29,742 atoms decayed during 365 days, which means that:

\lambda = \frac{29742}{365} = 81.485

The mean number of radioactive atoms that decay per day is 81.485.

b. Find the probability that on a given day, 50 radioactive atoms decayed.

This is P(X = 50). So

P(X = 50) = \frac{e^{-81.485}*(81.485)^{50}}{(50)!} = 0

0% probability that on a given day, 50 radioactive atoms decayed.

5 0
3 years ago
shirley is going to have the exterior of her home painted. tims painting charges  $250 plus $14 per hour. colorful prints charge
Alexandra [31]
x-\ number\ of\ hours\\\\
250+14x
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