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OLga [1]
3 years ago
11

Simplify the expression . Express your answer in scientific notation.

Mathematics
2 answers:
slamgirl [31]3 years ago
8 0

Fyiiuii hioytdfjk. Iiyhlo
Annette [7]3 years ago
6 0

Answer:

ghjgxgjgdfhjhgffghhgcfgghhxghbjhgxdfhhj

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Simplify the following expression. (10-4i)(4-5i)+(-15+20i)
Vikki [24]

Answer:

5-46i

Step-by-step explanation:

1. Multiply (10-4i) and (4-5i), I recomnd using foil:

40-50i-16+20i^2 + (-15+20i)

2. Remove the parenthesis around -15+20i

*we can do this since there is a "+":    

40-50i-16+20i^2 + (-15)+20

3. Simplify i^2

* i^2 is -1 by textbook defination:

40-50i-16+20(-1) + (-15)+20

4. Simplify

40-50i-16-20 + (-15)+20

6. Combine like terms:

-5-50i-16i+20i

5-46i

And the problem is done

3 0
3 years ago
How do you know when the model shows the final solution? How do you read the solution?
Korvikt [17]
It remains uncertain then. is it in science or math?
4 0
3 years ago
Find the probability that a point chosen at random will lie in the shaded area.
son4ous [18]
I think the answer is D
6 0
3 years ago
Suppose there are 100 people at airport security, 45 passengers were flying to Dallas of which 30 were men. 55 Passengers were f
Simora [160]

Answer:  A: 30% B: Yes they are independent events because they can both happen without the other one. C: No they are not mutually exclusive events because both of them can happen at the same time

Step-by-step explanation:

45 / 100 = .45 = 45%

.45 x 2/3 = .3

.3= 30%

7 0
3 years ago
If michael jordan has a vertical leap of 1.29 m, then what is his takeoff speed and his hang time
spin [16.1K]
The formula for the vertical height, h, attained with a vertical take off speed of u is
u² - 2gh = 0
where
g = 9.8 m/s², acceleration due to gravity.

Because h = 1.29 m, therefore
u² = 2*9.8*1.39 = 27.244
u = 5.2196 m/s

Also, the time of flight, t, required when the vertical take-off speed is u is given by
ut  - 0.5gt² = 0.
Therefore
5.2196t - 0.5*9.8*t² = 0
5.2196t - 4.9t² = 0
t(5.2196 - 4.9t) = 0
t = 0, or t = 5.2196/4.9 = 1.0652 s

t = 0 corresponds to take-off.
t = 1.0652 s corresponds to landing.
The hang time is 1.0652 s.

Answer:
Take-off speed = 5.22 m/s (nearest hundredth)
Hang time  = 1.065 s (nearest thousandth)

7 0
3 years ago
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