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Yuki888 [10]
3 years ago
10

Solve for x. 4x - 2 - x = 2x - 8 a. 5 b,-6 C. -2 D. -6/5

Mathematics
1 answer:
ValentinkaMS [17]3 years ago
7 0

Answer:

b, x = -6

Step-by-step explanation:

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Prove that the value of the expression does not depend on a:<br><br> a−(6a−(5a−8))
djyliett [7]

Step-by-step explanation:

a−(6a−(5a−8))

a-(6a-5a+8)

a-6a+5a-8

6a-6a-8

0-8

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so the answer doesn't depend on a

3 0
3 years ago
Please simplify: 5x + 2 (x - 3) = -2 (x - 1)
zysi [14]

Answer:

x= 8/9

Step-by-step explanation:

Open everything up to get 5x+2x-6=-2x+2. Move numbers with an x to the left side and without to the right to have 5x+2x+2x=2+6. Simplify to have 9x=8. Divide by 9 which leaves you with x= 8/9

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3 years ago
In MON, J, K, and L are midpoints. If JL = 11, LK = 13, and ON = 20, and JL || MN, LK || MO, and JK || ON, what is the length of
In-s [12.5K]

Answer:

The lengths of MN is 22 units, MO is 26 units and JK is 10 units

Step-by-step explanation:

<em>A l</em><em>ine segment</em><em> joining the </em><em>mid-points of two sides</em><em> in a triangle is </em><em>parallel to the third side</em><em> and </em><em>equal to half its length</em>

In Δ MON

∵ J, K, and L are mid-points

∵ JL // MN and LK // MO

∴ L is the mid-point of ON

∴ J is the mid-point of MO

∴ K is the mid-point of MN

∵ J, L are the mid-points of MO and ON

∵ JL is opposite to MN

→ By using the rule above

∴ JL = \frac{1}{2} MN

∵ JL = 11 units

∴ 11 = \frac{1}{2} MN

→ Multiply both sides by 2

∴ 22 = MN

∴ MN = 22 units

∵ K, L are the mid-points of MN and ON

∵ KL is opposite to MO

→ By using the rule above

∴ KL = \frac{1}{2} MO

∵ KL = 13 units

∴ 13 = \frac{1}{2} MO

→ Multiply both sides by 2

∴ 26 = MO

∴ MO = 26 units

∵ J, K are the mid-points of MO and MN

∵ JK is opposite to ON

→ By using the rule above

∴ JK = \frac{1}{2} ON

∵ ON =20 units

∴ JK = \frac{1}{2} (20)

∴ JK = 10 units

∴ The lengths of MN are 22 units, MO is 26 units and JK is 10 units

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