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3 years ago

Please help I’m stressing

Mathematics

1 answer:

Nookie1986 [14]3 years ago

5 0

It’s AAS because there are two congruent angles and one congruent side.

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choosing a card from a deck of cards numbered 10, 11, 12, ..., 25 and picking a day of the week WHAT IS THE PROBABILITY

lina2011 [118]

12 can you tell me what I got

3 0

3 years ago

1 х Given g(x)=

yarga [219]

(a) Since $g(x)=\sqrt[3]{x}$ and $h(x) = \frac1{x^3}$ , we have

$(g\circ h)(x) = g(h(x)) = g\left(\dfrac1{x^3}\right) = \sqrt{3}{\dfrac1{x^3}} = \dfrac1x$

We're given that

$(f \circ g \circ h)(x) = f(g(h(x))) = f\left(\dfrac1x\right) = \dfrac x{x+1}$

but we can rewrite this as

$\dfrac x{x+1} = \dfrac{\frac xx}{\frac xx + \frac1x} = \dfrac1{1+\frac1x}$

(bear in mind that we can only do this so long as x ≠ 0) so it follows that

$f\left(\dfrac1x\right) = \dfrac1{1+\frac1x} \implies \boxed{f(x) = \dfrac1{1+x}}$

(b) On its own, we may be tempted to conclude that the domain of $(f\circ g\circ h)(x) = \frac1{1+x}$ is simply x ≠ -1. But we should be more careful. The domain of a composite depends on each of the component functions involved.

$g(x) = \sqrt[3]{x}$ is defined for all x - no issue here.

$h(x) = \frac1{x^3}$ is defined for all x ≠ 0. Then $(g\circ h)(x) = \frac1x$ also has a domain of x ≠ 0.

$f(x) = \frac1{1+x}$ is defined for all x ≠ -1, but

$(f\circ g\circ h)(x)=f\left(\frac1x\right) = \dfrac1{1+\frac1x}$

is undefined not only at x = -1, but also at x = 0. So the domain of $(f\circ g\circ h)(x)$ is

$\left\{x\in\mathbb R \mid x\neq-1 \text{ and }x\neq0\right\}$

7 0

3 years ago

X=y-1 x+2y=5 what is the answer

olga55 [171]

3y=2x=5
hope this helps

8 0

3 years ago

Please help me!!!!!!!!!!

forsale [732]

Answer:

y = 240.3 ft to the nearest tenth.

Step-by-step explanation:

The bottom left angle = 31 degrees ( interior alternate angles).

tan 31 = y / 400

y = 400 tan 31

y = 240.34 ft.

4 0

3 years ago

Each school year, the seventh graders who study Life Science participate in a special field trip to the city zoo. In 2010, the s

Mrac [35]

Answer:

A. No it is not proportional.

B. The price goes up then down, and all years equal the same amount per student.

C. Constant proportionality starts at (0,0) and is constantly increasing.

D. $1,800 15×120=1,800

E. 95 students because 1,425÷15=95

3 0

3 years ago