Ernest would be swimming at 3.25 units on week 10
The explicit formula is given as:
Also, we have the following parameters
-- the initial distance
--- the difference between concurrent distances
In week 10, the value of n is 10.
Next, substitute 10 for n in the explicit formula
So, we have:
Subtract 1 from 10
Multiply 9 by 0.25
Add 1.0 and 2.25
Hence, Ernest would be swimming at 3.25 units on week 10
Read more about arithmetic sequence at:
We know that Hardy-Weinberg conditions include the following equations:
where
And where p = dominant, and q = recessive; this means that is equal to the homozygous dominant,
is the heterozygous, and
is the homozygous recessive .
So we have 100 total cats, with 4 having the recessive white coat color. That means we have a ratio of or 0.04. Let that equal our
value.
So when we solve for q, we get:
Now that we have our q value, we can use the other equation to find p:
So then we can solve for our heterozygous population:
This is the ratio of the population. So we then multiply this number by 100 to get the number of cats that are heterozygous:
So now we know that there are 32 heterozygous cats in the population.
Incomplete question. Attached is the image of the map below.
<u>Explanation:</u>
From the map, we could notice the contour lines around the Chimney Bluff areas are closely packed together. In other words, the spacing between the contour lines is narrower than those found in other locations.
This assertion is accurate because it is a standard practice in many maps to indicate the steepness of an area by having the contour lines in close proximity.
