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Amanda [17]
3 years ago
10

Find the sum.

Mathematics
2 answers:
Ilia_Sergeevich [38]3 years ago
6 0

Answer:

B. 16p+6

Step-by-step explanation:

Aleonysh [2.5K]3 years ago
5 0

Answer:

B . 16p + 6

Step-by-step explanation:

12p + 9 + 4p -3

collect like terms

(12p + 4p) + (9 - 3)

16p + 6

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x = 5 - 3y and y = - 7/3 + 5x/3

Step-by-step explanation:

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The difference of three times a number and 16 is at least 8
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Deb Boon is single, claims 2 allowances and earns $293.23 each week. If each weekly allowance is $63.46, how much is Deb's taxab
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1. Determine the discriminant and nature of roots of each quadratic equation.
Fiesta28 [93]

Answer:

Please check the explanation.

Step-by-step explanation:

The general quadratic equation is

ax²+bx+c=0

The discriminant = D = b² - 4ac

When b² - 4ac = 0 there is one real root.

When b² - 4ac > 0 there are two real roots.

When b² - 4ac < 0 there are two complex roots.

1) x² -6x + 9=0

On comparing with given quadratic equation x² -6x + 9=0

a = 1, b=-6, c=9

D = b² - 4ac

   = (-6)² - 4(1)(9)

   = 36 - 36

   = 0

D = 0

Thus, there is one real root of quadratic equation x² -6x + 9=0.

2) x² -4x + 3=0

On comparing with given quadratic equation x² -4x + 3=0

a = 1, b=-4, c=3

D = b² - 4ac

   = (-4)² - 4(1)(3)

   = 16 - 12

   = 4

D > 0

Thus, there are two real roots of quadratic equation x² -4x + 3=0.

3)  x² -7x - 4=0

On comparing with given quadratic equation x² -7x - 4=0

a = 1, b=-7, c=-4

D = b² - 4ac

   = (-7)² - 4(1)(-4)

   = 49 + 16

   = 65

D > 0

Thus, there are two real roots of quadratic equation x² -7x - 4=0

4)  2x² +3x +5=0

On comparing with given quadratic equation 2x² +3x +5=0

a = 2, b=3, c=5

D = b² - 4ac

   = (3)² - 4(2)(5)

   = 9 - 40

   = -31

D < 0

Thus, there are two complex roots of quadratic equation 2x² +3x +5=0

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Jonathan calls his mother 2 times every week.
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Answer:

2w=c 2 times each week so 2 times how many weeks

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