Question

What is the sqaure root of (x-3/7) divided by 12x+7 divided by 76.3x?

Answer 1

Answer:

$\sqrt{\frac{3x}{3} } + \frac{10}{109} x$

Step by step:

$\sqrt{x-\frac{3}{7}$ = $\sqrt{\frac{49x-21}{7} }$

$\sqrt{\frac{49x-21}{7} }$ ÷ 12x+7=$\sqrt{\frac{7x-3x}{12}} + 7$

$\sqrt{\frac{7x-3x}{12}} + 7$ ÷ 76.3x = $\sqrt{\frac{3x}{3} } + \frac{10}{109} x$

Hope this helps!