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3 years ago

The perimiter of each face of a rubiks cube is 22.2 centimeters. What is the length of and edge of the rubiks cube?

Mathematics

1 answer:

ivanzaharov [21]3 years ago

5 0

Answer:

3.7 cm

Step-by-step explanation:

22.2 / 6 = 2.7

Hope that helps!

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Estimate to 920,026-535,722

Sonja [21]

900000000000 i would think because 5 above is round up 4 and below round down

4 0

3 years ago

Read 2 more answers

I have another Brainliest reward

Luba_88 [7]

San Antonio to Dallas
65mph with 277 mi
277/ 65 = 4.26 hours
4.26 hours < 4.5 hours
so answer is YES

-----------------
Dallas to San Antonio: 277/4.75 = 58.32 mph
Lubbock to El Paso : 344/4.5 = 76.44 mph
San Antonio to Abilene: 261 / 4.25 = 61.41 mph
Dallas to Abilene: 185 / 3 = 61.67 mph

answer
lowest speed is :
Dallas to San Antonio in 4 3/4 hours

3 0

3 years ago

The given two-parameter family is a solution of the indicated differential equation on the interval

mr_godi [17]

Answer:

I do 1 option for you as an example, you need to check the leftover by yourself.

Step-by-step explanation:

for d) y(0) = 0 and y'(pi) =0

$y(0) = C_1e^0cos(0)+ C_2 e^0 sin(0) = 0 \longrightarrow C_1 = 0$

$y(x) ' = C_1e^x cos(x) - C_1e^x sin (x) + C_2e^x sin(x) + C_2e^x cos(x)$

$y(\pi)'=C_1e^\pi cos(\pi)- C_1e^\pi sin(\pi)+ C_2e^\pi sin(\pi) + C_2e^\pi cos (\pi)$

Replace $C_1 = 0$ we have

$y'(\pi) = -C_2e^\pi = 0$

if and only if $C_2 =0$

Hence the given solution does not work.

then, d is NOT the correct answer.

3 0

3 years ago

How many times can 535 go into 1035

ICE Princess25 [194]

Only once, any number higher will pass it

3 0

3 years ago

Create the equation of a quadratic function with a vertex of (5,6) and a y-intercept of -69

Elena L [17]

If the y-intercept is at -69, meaning the point is (0, -69), thus x = 0, y = -69

$\bf ~~~~~~\textit{parabola vertex form}
\\\\
\begin{array}{llll}
\boxed{y=a(x- h)^2+ k}\\\\
x=a(y- k)^2+ h
\end{array}
\qquad\qquad
vertex~~(\stackrel{}{ h},\stackrel{}{ k})\\\\
-------------------------------\\\\
vertex~(5,6)\quad 
\begin{cases}
x=5\\
y=6
\end{cases}\implies y=a(x-5)^2+6
\\\\\\
\textit{we also know that }
\begin{cases}
x=0\\
y=-69
\end{cases}\implies -69=a(0-5)^2+6
\\\\\\
-75=25a\implies \cfrac{-75}{25}=a\implies a=-3
\\\\\\
therefore\qquad \boxed{y=-3(x-5)^2+6}$

3 0

3 years ago