Answer:
Follows are the solution to this question:
Step-by-step explanation:
Technician selects three out of 5 systems
In C(5,3)=10ways, this can be achieved
In part a:
Space sample chooses 3 of a 5 systems
In point b:
A =MODULE WHICH INCLUDE M1 minimal amount of effort
Outcomes probable =
In point c:
B = highest effort that is 
Potential result=
In point d:
In point e:
In point f:
In point g:
In point h:
The Answer Is A Fraction y= 151/47
Find the difference vertically( North and South) and the difference horizontally ( East and West)
Then use the Pythagorean Theorem.
600 North - 200 South = 400 m
400 West - 100 East = 300 m
Now using the Pythagorean Theorem;
400^2 + 300^2 = total displacement^2
Total displacement^2 = 160,000 + 90,000
Total displacement^2 = 250,000
Total displacement = √250,000
Total displacement = 500 m
Your answer would be A because $4800 is your starting number and it increases 2% every year. How much is it in 20 years?
You use the formula ab^x
a is your starting number
b is the percentage
x is always the length of time
Since you are increasing and trying to get its worth larger than what it was before you use a number larger than one hundred percent in this case the number would be 1.02.
Y=4800(1.02)^20
Y=$7132.55
Answer:
?=7
Step-by-step explanation:
Here is a cool trick that I believe only works with 9.
Add the numbers, 3+9+9+8+x= divisible by 9.
3+9+9+7+8 is 36 which is the only number divisible by 9.
