. If 2n - 5m + 10 = 0, find<br>i) m, when n=2 ii) n, when m=5

Jerry spend $42 to by some shirts. Each of the shirts cost the same whole-dollar amount. How many shirts could he have bought?

ikadub [295]

You answer is 6 shirts good sir. Have a nice day. :D

5 0

4 years ago

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Find the appropriate rejection regions for the large-sample test statistic z in these cases. (Round your answers to two decimal

Usimov [2.4K]

Answer:

a) We have that the significance is given by $\alpha =0.01$ and we know that we have a right tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 1% of the area on the right and 99% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.01,0,1)"

And we got for this case $z_{crit}=2.33$

So then the rejection region would be $z>2.33$

b) We have that the significance is given by $\alpha =0.05$ , $\alpha/2 =0.025$ and we know that we have a two tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 2.5% of the area on the right and 97.5% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.025,0,1)"

And we got for this case $z_{crit}=\pm 1.96$

So then the rejection region would be $z>1.96 \cup z$

Step-by-step explanation:

Part a

We have that the significance is given by $\alpha =0.01$ and we know that we have a right tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 1% of the area on the right and 99% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.01,0,1)"

And we got for this case $z_{crit}=2.33$

So then the rejection region would be $z>2.33$

Part b

We have that the significance is given by $\alpha =0.05$ , $\alpha/2 =0.025$ and we know that we have a two tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 2.5% of the area on the right and 97.5% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.025,0,1)"

And we got for this case $z_{crit}=\pm 1.96$

So then the rejection region would be $z>1.96 \cup z$

7 0

4 years ago

Anu

bija089 [108]

Answer:

Circumference of Circle B=19.625cm

Step-by-step explanation:

The circumference formula is: 2pie(r) = pie(d)

We have diameter of the first circle which is 6. Now, because the diameter of second circle is 25% greater than this,

Hence, we add 25% in 6:

6+25/100 =6+0.25=6.25 cm

Therefore, we have diameter of 6.25 for circle B.

Now, we need to find the circumference of the Circle A.

circumference= pie(d) = pie(6)= 3.14times6= 18.84

Now use the proportional reasoning to find Circumference of Circle B:

circumference of Circle A/diameter Circle A = circumference of Circle B/diameter Circle B

18.84/6=circumference of Circle B/6.25

Cross multiply and divide:

(18.84times6.25)/6 = Circumference of Circle B

Solve:

Circumference of Circle B=19.625cm

Hope this helps!

Mark brainliest if you think i helped! Would really appreciate!

7 0

3 years ago

Help me asap ill give brainliest

disa [49]

Answer:

-6, -2, 1, 8

Step-by-step explanation:

4 0

4 years ago

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Two of the lights at the local stadium are flickering. They both just flickered at the same time. One of the lights flickers eve

irinina [24]

1,665
because 777+888 = 1,665

7 0

4 years ago

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. If 2n - 5m + 10 = 0, findi) m, when n=2 ii) n, when m=5​

. If 2n - 5m + 10 = 0, findi) m, when n=2 ii) n, when m=5