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harkovskaia [24]
3 years ago
12

4 plus 4 minus 4 times 4 divided by 4? Are you smart enough to figure this out

Mathematics
2 answers:
Mariulka [41]3 years ago
6 0

Step-by-step explanation:

A. 4÷4=8 -4×4=-16 4÷4=1

8 subtract -16 ÷4 = 4

B. 4+4−4×4÷4 overall =4

-Dominant- [34]3 years ago
5 0

Answer:

4

Step-by-step explanation:

use pemdas.

4+4-4x4/4

4+4-16/4

4+4-4

8-4

4

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The equation having null set as its solution set is
KIM [24]

Answer:

  B) x = e^x

Step-by-step explanation:

The graphs of y = e^x and y = x never intersect, so the solution set will be the empty (null) set for ...

  x = e^x

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There is one intersection of y=x with cos(x) and with sin(x). There are an infinite number of solutions for x = tan(x).

4 0
3 years ago
I don’t understand how to do this question so can anyone help me?
nataly862011 [7]

Step-by-step explanation:

from the line above

P1 = -2

P2 = -1

P3 = 1/3

P4 = 2/3

P5 = 1 1/2 = 3/2

The product of P1 to P5,P

=> P = -2×-1×1/3×2/3×3/2 = 2/3

8 0
2 years ago
<img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B2x%7D%20%2B%2012%20%3D%20x%20%2B%208%20" id="TexFormula1" title=" \sqrt{2x} + 12
Helga [31]
First note that x\ge0; otherwise \sqrt{2x} is undefined as long as we're only looking for real solutions.

We can write

\sqrt{2x}+12=x+8
\sqrt{2x}=x-4
2x=(x-4)^2
2x=x^2-8x+16
x^2-10x+16=0
(x-8)(x-2)=0

\implies x=8,x=2
4 0
3 years ago
arrange the expressions in the correct sequence to rationalize the denominator of the expression -(2)/(\sqrt(x+y-2)-\sqrt(x+y+2)
cupoosta [38]
We have to rationalize the denominator:
\frac{-2}{ \sqrt{x+y-2} - \sqrt{x+y+2} } = \\  \frac{-2}{ \sqrt{x+y-2} -  \sqrt{x+y+2} }* \frac{ \sqrt{x+y-2}+ \sqrt{x+y+2}  }{ \sqrt{x+y-2}+ \sqrt{x+y+2}  }= \\  \frac{-2*( \sqrt{x+y-2}+ \sqrt{x+y+2})  }{x+y-2-(x+y+2)}= \\  \frac{-2*( \sqrt{x+y-2}+ \sqrt{x+y+2})  }{x+y-2-x-y-2}= \\  \frac{-2*( \sqrt{x+y-2}+ \sqrt{x+y+2}  }{-4}= \\  \frac{ \sqrt{x+y-2}+ \sqrt{x+y+2}  }{2}
6 0
2 years ago
Read 2 more answers
With a picture eqation
butalik [34]
I don’t mean to take point but i do not see a picture :(
7 0
2 years ago
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