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3 years ago

I need help with this question

Mathematics

1 answer:

AlexFokin [52]3 years ago

6 0

Q + s = q + 1, we know because you can substitute s for 1 according to the number line.

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Diane and Darryl both work in sales. Diane gets paid a base salary of $200 per week and $10 per hour. Darryl gets paid a base sa

Licemer1 [7]

Answer:

A: Diane earns 200 + (10×20)= 400

B: Darryl earns (400-250)/20= $7.50 per hour

8 0

3 years ago

At a 20th high school reunion, all the classmates were asked the number of children they had. The probability of having a partic

finlep [7]

Answer:

a) We need to check two conditions:

1) $\sum_{i=1}^n P_i = 1$

$0.05+0.14+0.34+0.24+0.11+0.07+0.02+0.02+0.01= 1$

2) $P_i \geq 0 , \forall i=1,2,...,n$

So we satisfy the two conditions so then we have a probability distribution

b) $P(C \geq 1)$

And we can use the complement rule and we got:

$P(C \geq 1)= 1-P(C$

c) $P(C=0) = 0.05$

d) For this case we see that the result from part b use the probability calculated from part c using the complement rule.

Step-by-step explanation:

For this case we have the following probability distribution given:

C 0 1 2 3 4 5 6 7 8

P 0.05 0.14 0.34 0.24 0.11 0.07 0.02 0.02 0.01

And we assume the following questions:

a) Verify that this is a probability distribution

We need to check two conditions:

1) $\sum_{i=1}^n P_i = 1$

$0.05+0.14+0.34+0.24+0.11+0.07+0.02+0.02+0.01= 1$

2) $P_i \geq 0 , \forall i=1,2,...,n$

So we satisfy the two conditions so then we have a probability distribution

b) What is the probability one randonmly chosen classmate has at least one child

For this case we want this probability:

$P(C \geq 1)$

And we can use the complement rule and we got:

$P(C \geq 1)= 1-P(C$

c) What is the probability one randonmly chosen classmate has no children

For this case we want this probability:

$P(C=0) = 0.05$

d) Look at the answers for parts b and c and explain their relationship

For this case we see that the result from part b use the probability calculated from part c using the complement rule.

5 0

3 years ago

Given that the sec A = 13/5 and A is in QIV, determine exact value for the sin A.

AysviL [449]

Answer:

The exact value of sin A is opp/hyp = -12/13

Step-by-step explanation:

If A is in Quadrant IV then the "opposite side" is negative and the "adjacent side" is positive. Since sec A = hyp / adj = 13 / 5 and since opp^2 + adj^2 must add up to hyp^2, Therefore y = √(hyp^2 - adj^2), or

y = -√(13^2 - 25) = -√144 = 12.

The exact value of sin A is opp/hyp = -12/13

6 0

3 years ago

Given the following sequence, find the 23rd term: 10.5, 11, 11.5, 12, 12.5, . . .

4vir4ik [10]

10.5, 11, 11.5, 12, 12.5...this is an arithmetic sequence with a common difference of 0.5

an = a1 + (n - 1) * d
n = term to find = 23
a1 = first term = 10.5
d = common difference = 0.5

sub and solve

a(23) = 10.5 + (23 - 1) * 0.5
a(23) = 10.5 + 22 * 0.5
a(23) = 10.5 + 11
a(23) = 21.5 <===

6 0

3 years ago

The surface area of the cone is 43.75pie cm^2. What is the slant height of the cone and the diameter is 5

Masteriza [31]

If the diameter of the cone is 5, then the radius of it will be half that, or 2.5, thus

$\bf \textit{total surface area of a cone}\\\\
SA=\pi r\stackrel{slant~height}{\sqrt{r^2+h^2}}+\pi r^2~~
\begin{cases}
r=radius\\
h=height\\
------\\
SA=43.75\pi \\
r=2.5
\end{cases}
\\\\\\
43.75\pi =\pi (2.5)\sqrt{r^2+h^2}+\pi (2.5)^2
\\\\\\
43.75\pi -\pi (2.5)^2=2.5\pi \sqrt{r^2+h^2}
\\\\\\
43.75\pi -6.25\pi =2.5\pi \sqrt{r^2+h^2}\implies 37.5\pi =2.5\pi \sqrt{r^2+h^2}
\\\\\\
\cfrac{37.5\pi }{2.5\pi }=\sqrt{r^2+h^2}\implies 15=\sqrt{r^2+h^2}$

3 0

4 years ago

I need help with this question​

I need help with this question