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kvasek [131]
3 years ago
12

I need help with this question​

Mathematics
1 answer:
AlexFokin [52]3 years ago
6 0
Q + s = q + 1, we know because you can substitute s for 1 according to the number line.
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Match each equation to a solution.<br> 2X=64
Marysya12 [62]
X=32

2x=64 divide each side by 2
5 0
3 years ago
According to Descartes's rule of sign, how many possible positive and negative roots are there for the equation
damaskus [11]
<h2>Descartes Rule of Sign</h2><h3>Answer:</h3>

There are 3 Real Roots for the Equation

<h3>Step-by-step explanation:</h3>

According to Descartes Rule of Sign, The maximum number of real roots a polynomial equation has is the number of times the sign of term changes from a higher power term to a lower power term.

In the given equation, 0=-4x^6-3x^5+2x^2-4x+1, we can already see that from \red -4x^6 to \red -3x^5 we can see that the sign didn't change so there might be no real roots. From \red -3x^5 to \blue +2x^2, we can see that the signs change so we now know that there might be 1 real root for equation. From \blue +2x^2 to \red -4x, the signs changed so there might be 2 real roots. From \red -4x to \blue +1, it changed again so there might be 3 real roots. There are no other term with lesser power to compare for \blue +1 so we are left with 3 real roots.

7 0
3 years ago
Read 2 more answers
Find the polynomial of minimum degree, with real coefficients, zeros at x=4±2⋅i and x=−8, and y-intercept at −480. Write your an
valkas [14]

Answer:

The polynomial of minimum degree is p(x) = x^{4}-3\cdot x^{3}-44\cdot x^{2}+292\cdot x-480.

Step-by-step explanation:

According to the statement, we appreciate that polynomial pass through the following points:

(i) (4 + 2\,i,0), (ii) (4 - 2\,i, 0), (iii) (-8, 0), (iv) (0, -480)

From Algebra we know that any n-th grade polynomial can be constructed by knowing n+1 different points. Hence, the polynomial of minimum degree is a quartic function. The polynomial has the following form:

p(x) = (x-4-2\,i)\cdot (x-4+2\,i)\cdot (x+8)\cdot (x-r_{1})

We proceed to expand the expression until standard form is obtained:

p(x) = (x^{2}-4\cdot x-2\,i\cdot x-4\cdot x +16+8\,i+2\,i\cdot x-8\,i+4)\cdot (x+8)\cdot (x-r_{1})

p(x) = (x^{2}-8\cdot x+20)\cdot (x+8)\cdot (x-r_{1})

p(x) = (x^{3}-8\cdot x^{2}+20\cdot x +8\cdot x^{2}-64\cdot x+160)\cdot (x-r_{1})

p(x) = (x^{3}-44\cdot x +160)\cdot (x-r_{1})

If we know that p (0) = -480, then:

-480=160\cdot (-r_{1})

-160\cdot r_{1} = -480

r_{1} = 3

Then, the polynomial is:

p(x) = (x^{3}-44\cdot x +160)\cdot (x-3)

p(x) = x^{4}-44\cdot x^{2}+160\cdot x-3\cdot x^{3}+132\cdot x -480

p(x) = x^{4}-3\cdot x^{3}-44\cdot x^{2}+292\cdot x-480

The polynomial of minimum degree is p(x) = x^{4}-3\cdot x^{3}-44\cdot x^{2}+292\cdot x-480.

5 0
3 years ago
I need Answer Immediately!!!!!!
m_a_m_a [10]
It will be 12y mmmmmmmmmmmmmmmdmdkdjnejddjhsjssj
6 0
3 years ago
A bicycle that usually sells for 230 is on sale for 15% off. Find the sale price
SSSSS [86.1K]

Answer: $172.50

Step-by-step explanation: Method 1:

The original price of the item is $230.

The discount is 25%.

Let's find 25% of $230.

25% of $230 = 0.25 * $230 = $57.50

The discount amount is $57.50.

Now we subtract the amount of the discount from the original cost.

Sale price = $230 - $57.50 = $172.50

Method 2.

The original price is $230.

That means that $230 is 100% of the price since 100% of a thing means the entire thing.

Since the discount is 25% of the price, we subtract 25% from 100%, 100% - 25% = 75%.

The sale price is 75% of the original price.

Now we find 75% of $230.

75% of $230 = 0.75 * $230 = $172.50

8 0
4 years ago
Read 2 more answers
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