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klio [65]
3 years ago
11

What is an equation of the line that passes through the points (-6,2) and (-6, 6)?

Mathematics
1 answer:
iogann1982 [59]3 years ago
5 0

Answer:

Step-by-step explanation:

y

=

−

2

3

x

+

2

Explanation:

Given that we have the slope and a point on the graph we can use the point slope formula to find the equation of the line.

Point-Slope Formula:

y

−

y

1

=

m

(

x

−

x

1

)

, where

m

is the slope of the line and

x

1

and

y

1

are x and y coordinates of a given point.

We can summarize the information already given:

m

=

−

2

3

x

1

=

6

y

1

=

−

2

Using this information, we can substitute these values onto the point-slope formula:

y

−

(

−

2

)

=

−

2

3

(

x

−

(

6

)

)

y

+

2

=

−

2

3

(

x

−

6

)

The equation above is the equation of the line in point-slope form. If we wanted to have the equation in

y

=

m

x

+

b

form then we simply solve the equation above for

y

y

+

2

=

−

2

3

x

+

12

3

y

+

2

−

2

=

−

2

3

x

+

12

3

−

2

y

=

−

2

3

x

+

12

3

−

2

(

3

3

)

y

=

−

2

3

x

+

12

3

−

6

3

y

=

−

2

3

x

+

6

3

y

=

−

2

3

x

+

2

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       ----------------------

          2a

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       ----------------------

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       ----------------------

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     --------------------   or                    -------------------  

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6 0
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1. First, you must apply the formula for calculate the sum of the interior angles of a regular polygon, which is shown below:


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 2. Then, the sum of the interior angles of the pentagon, is:


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 3. The problem says that the measure of each of the other interior angles is equal to the sum of the measures of the two acute angles and now you know that the sum of all the angles is 540°, then, you have:


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