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Zepler [3.9K]
3 years ago
9

Brian is wrapping a present. If his box is in the shape of a cube with a side length of 7 inches, what is the minimum amount of

paper Brian would need to cover the present?
Mathematics
1 answer:
chubhunter [2.5K]3 years ago
5 0
Surface area is 6s^2, so 6(7^2) is 294. The minimum amount would be 294 inches^2 of wrapper paper.
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(x_ {1}, y_ {1}) :( 4, -4)\\(x_ {2}, y_ {2}) :( 8, -10)\\m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}} = \frac {-10 - (- 4)} {8-4} = \frac {-10+ 4} {4} = \frac {-6} {4} = - \frac {3} {2}

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ANswer:

y = - \frac {3} {2} +2

4 0
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