All categories

3 years ago

I need some help…

Mathematics

1 answer:

barxatty [35]3 years ago

4 0

Use the formula for compounded interest and plug in variable to solve for the amount. The picture should help

You might be interested in

The width of a rectangle stage is 55% of its length. The stage is 120 feet long .What is the area?

saveliy_v [14]

Answer:

7920 square feet.

step -by- step explanation.

From the the question, the

Length, l= 120 feet.

Width, w= 55% of l

This implies that;

w=0.55×120=66 feet.

Area of rectangle is given by the relation ;

$A =l \times w$

By substitution,

$A =120\times 66$

$\implies A =7920$

Therefore the area of the rectangular stage is 7920 square feet.

5 0

3 years ago

Data collected at Toronto Pearson International Airport suggests that an exponential distribution with mean value 2725hours is a

Ivan

Answer:

a) What is the probability that the duration of a particular rainfall event at this location is at least 2 hours?

We want this probability"

$P(X >2) = 1-P(X\leq 2) = 1-(1- e^{-0.367 *2})=e^{-0.367 *2}= 0.48$

At most 3 hours?

$P(X \leq 3) = F(3) = 1-e^{-0.367*3}= 1-0.333 =0.667$

b) What is the probability that rainfall duration exceeds the mean value by more than 2 standard deviations?

$P(X > 2.725 + 2*5.540) = P(X>13.62) = 1-P(X$

What is the probability that it is less than the mean value by more than one standard deviation?

$P(X$

Step-by-step explanation:

Previous concepts

The exponential distribution is "the probability distribution of the time between events in a Poisson process (a process in which events occur continuously and independently at a constant average rate). It is a particular case of the gamma distribution". The probability density function is given by:

$P(X=x)=\lambda e^{-\lambda x}$

The cumulative distribution for this function is given by:

$F(X) = 1- e^{-\lambda x}, x\ geq 0$

We know the value for the mean on this case we have that :

$mean = \frac{1}{\lambda}$

$\lambda = \frac{1}{Mean}= \frac{1}{2.725}=0.367$

Solution to the problem

Part a

What is the probability that the duration of a particular rainfall event at this location is at least 2 hours?

We want this probability"

$P(X >2) = 1-P(X\leq 2) = 1-(1- e^{-0.367 *2})=e^{-0.367 *2}= 0.48$

At most 3 hours?

$P(X \leq 3) = F(3) = 1-e^{-0.367*3}= 1-0.333 =0.667$

Part b

What is the probability that rainfall duration exceeds the mean value by more than 2 standard deviations?

The variance for the esponential distribution is given by: $Var(X) =\frac{1}{\lambda^2}$

And the deviation would be:

$Sd(X) = \frac{1}{\lambda}= \frac{1}{0.367}= 2.725$

And the mean is given by $Mean = 2.725$

Two deviations correspond to 5.540, so we want this probability:

$P(X > 2.725 + 2*5.540) = P(X>13.62) = 1-P(X$

What is the probability that it is less than the mean value by more than one standard deviation?

For this case we want this probablity:

$P(X$

8 0

4 years ago

If the absolute value of a number is added to the original number will the sum always equal 0

lbvjy [14]

Not necessarily. the absolute value of a number is that number's distance from 0 on a number line. if your taking the absolute value of a negative value, what you stated would be true. however, what if you took the absolute value of a positive number? hope that answers your question.

8 0

3 years ago

Can someone help me with this question please.

kiruha [24]

Answer =3/10

Adding all the frequency... 13+6+9+12=40

And we looking probability of picking yellow... Hence... Yellow /total =12/40

Hence giving 3/10

3 0

4 years ago

Please help me my grade is a D

Alenkasestr [34]

The first one is false and the second one is 1.5 2 is the outlier

4 0

3 years ago