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3 years ago

Find the mean, median, and mode of the data: 2.4, 1.9, 3.3, 3.5, 3.2, 2.7, 1.1, 20.9, 2.4.

Mathematics

2 answers:

dmitriy555 [2]3 years ago

7 0

Answer:

I would need a picture to answer the question

zysi [14]3 years ago

4 0

Do you have pic it’s hard this way

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Write an equation or inequality to represent the scenario:

aniked [119]

<h3>The value of x is equal to 1.</h3><h3>6(x + 2) = 20x - 2</h3>

Distributive property.

6x + 12 = 20x - 2

Add 2 to both sides.

6x + 14 = 20x

Subtract 16x from both sides.

14 = 14x

Divide both sides by x.

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3 years ago

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gayaneshka [121]

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3 years ago

If 20 is 40% of a value, what is that value?

podryga [215]

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4 years ago

I had four numbers: 12, 8, 4, and ????? However, I remember that their average was 11. Please, help me to remember the number th

Anestetic [448]

Answer:

The number was 20

Step-by-step explanation:

As the average is 11 and the numbers are 4, so the total sum of numbers will be 11X4=44. now the sum of three numbers are (20+8+4)=24. So the last number will be= (44-24)=20. :)

5 0

3 years ago

Read 2 more answers

Without using a calculator, match each expression to the correct point.

solniwko [45]

Answer:

The locations of each irrational number are the following:

$\sqrt{16}$ - Point $a$

$\sqrt{27}$ - Point $b$

$\sqrt{32}$ - Point $c$

Step-by-step explanation:

$\sqrt{16}$ is an irrational number that is also rational, since $4^{2} = 16$ . Then, $\sqrt{16}$ must be point $a$ .

Both $\sqrt{27}$ and $\sqrt{32}$ are greater than $\sqrt{25} = 5$ and less than $\sqrt{36} = 6$ . Then, both are between 5 and 6. Since $\sqrt{27} < \sqrt{32}$ , $\sqrt{27}$ must be point $b$ and $\sqrt{32}$ must be point $c$ .

3 0

3 years ago