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ch4aika [34]
3 years ago
9

Find the mean, median, and mode of the data: 2.4, 1.9, 3.3, 3.5, 3.2, 2.7, 1.1, 20.9, 2.4.

Mathematics
2 answers:
dmitriy555 [2]3 years ago
7 0

Answer:

I would need a picture to answer the question

zysi [14]3 years ago
4 0
Do you have pic it’s hard this way
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Am I correct?<br> will mark brainliest
jeka94

Answer:

Rhombus

Step-by-step explanation:

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Tom and his friend are driving to Tameka is taking the same 432-mile round trip as Tom to Louisville, but renting a car at a spe
Akimi4 [234]

Answer: The correct answer is $ 134.42 for the gas and the rental.

Step-by-step explanation: The trip is 432 miles and Tameka's car gets 35 miles to the gallon. So we have to figure out how many gallons we would use for the entire trip by dividing 432 by 35= 12.34 gallons of gas.

We know gas is $2.79 a gallon so we multiply 2.79 (cost per gallon) x 12.34 ( our total gallons used) =$34.43 in gasoline.

The rental costs $99.99 so we add that cost and the cost of the gas $34.43= $134.42 the total cost of the rental and the gas.

6 0
3 years ago
Solve the question and check the solution. Express numbers as integers or simplified fractions. 5(m+5)=7m+9
Yanka [14]

Answer:

m = 8

Step-by-step explanation:

5(m+5)=7m+9   (distribute & evaluate parenthesis)

5(m)+5(5)=7m+9

5m + 25 = 7m + 9  (move all m-terms to one side and constants to the other)

5m - 7m = 9 - 25  (evaluate both sides)

-2m = -16 (divide both sides by -2)

m = (-16) / ( -2) = 8

7 0
3 years ago
0.4(5x – 12) + 0.5x = 15.2
kvasek [131]

<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em> </em><em>⤴</em>

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3 0
3 years ago
Read 2 more answers
A ship leaves port at 1:00 P.M. and travels S35°E at the rate of 27 mi/hr. Another ship leaves the same port at 1:30 P.M. and tr
Len [333]

To solve this problem you must apply the proccedure shown below:

1. You must apply the Law of Cosines, as you can see in the figure attached. Then:

- The first ship travels at 27 mi/hr in for two hours. Therefore, the side a is:

a=(27 mi/hr)(2 hr)=54mi

- The second ship travels at 18 mi/hr for 1.5 hours. Therefore, the side b is:

b=(18mi/hr)(1.5hr)=27mi

- Now, you can calculate c:

c=\sqrt{54^{2}+27^{2}-2(54)(27)Cos(55)}=44 mi

The answer is: 44 miles

8 0
3 years ago
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