5^(x+7)=(1/625)^(2x-13)
We move all terms to the left:
5^(x+7)-((1/625)^(2x-13))=0
Domain of the equation: 625)^(2x-13))!=0
x∈R
We add all the numbers together, and all the variables
5^(x+7)-((+1/625)^(2x-13))=0
We multiply all the terms by the denominator
(5^(x+7))*625)^(2x+1-13))-((=0
We add all the numbers together, and all the variables
(5^(x+7))*625)^(2x-12))-((=0
We add all the numbers together, and all the variables
(5^(x+7))*625)^(2x=0
not sure if this is right :/
You can do it this think and if you can't I will help you
Answer:
This is ezz lol.
Step-by-step explanation:
Your answer would be 1/5
Answer:
2<x<8
Here is the answer to he above question you asked. (I have to type at least 20 words to post my answer...)
Answer:
i. terms = 5xy(z)^2 , -3zy
coefficient = 5 and -3
ii. terms = 1 , X ,x^2
coefficient = 1 , 1
iv. terms = 3 , -pq , qr, -rp
coefficient = -1 ,1 , -1
v. terms = X/2 , y/2 , -xy
coefficient= 1/2 ,1/2 and -1
