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Vlad1618 [11]
3 years ago
13

Initially 100 milligrams of a radioactive substance was present. After 8 hours the mass had decreased by 2%. If the rate of deca

y is proportional to the amount of the substance present at time t, determine the half-life of the radioactive substance. (Round your answer to one decimal place.)
Mathematics
1 answer:
4vir4ik [10]3 years ago
5 0

Answer:

The half life of the radioactive substance is 277 hours.

Step-by-step explanation:

initial mass, No = 100 mg

mass decayed = 2% = 2 mg

Mass remained , N = 98 mg

time, t = 8 hours

Let the half life is T.

Use the equation of radioactivity

N = No\times e^{\frac{-0.693 t}{T}}\\\\98 = 100 \times e^{\frac{-0.693\times 8}{T}}\\\\0.98 = e^{\frac{-5.54}{T}}\\\\ln 0.98 = -\frac{5.54}{T}\\\\-0.02= -\frac{5.54}{T}\\\\T =  277 hours  

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If f(x) = 2x - 4 and g(x)= -5x + 6, then what is f(g(x))?
Nikitich [7]

Answer:

B. f(g(x)) = -10x + 8

Step-by-step explanation:

When evaluating f(g(x)), substitute what g(x) is in place of g(x).

So instead of

f(g(x))

the function would be:

f(-5x + 6).

Now all you have to do is evaluate this.

To evaluate this function, substitute the value inside the f(x) for all instances of x in the equation.

f(x) = 2x - 4

f(-5x + 6) = 2(-5x + 6) - 4

f(-5x + 6) = -10x + 12 - 4

f(-5x + 6) = -10x + 8

Therefore, f(g(x)) = -10x + 8.

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3 years ago
An airline experiences a no-show rate of 6%. What is the maximum number of reservations that it could accept for a flight with a
sasho [114]

Answer:

Step-by-step explanation:

Use the normal approximation to the binomial distribution

mean µ = np

standard deviation σ = √npq

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Given that

q = 6% =0.06

Then, p = 1-q = 1-0.06 = 0.94

Therefore:

µ = pn

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Using z-scores:

z = (x — µ )/σ

Using the data above

1.645 = (160 — 0.94n)/√(0.0564n)

Cross multiply

1.645√0.0564n = 160—0.94n

Square both sides

1.645²× 0.0564n = (160-0.94n)

0.153n=25600— 300.8n + 0.8836n²

0.8836n²-300.8n-0.153n +25600=0

0.8836n² — 300.953n + 25600 = 0

Using quadratic formula method.

a = 0.8836 b = -300.953 c = 25600

n = [-b±√(b²-4ac)]/2a

n = [--300.953±√((-300.953)²-4×0.8836×25600)] / (2 × 0.8836)

n = [300.953±√(92.07)]/1.7672

n = (300.953±9.6)/1.762

n = (300.953-9.6)/1.762

n = 168.22

Or

n = (300953+9.6)/1.762

n = 176.25

The maximum number of reservation is approximately 168.

6 0
4 years ago
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Step2247 [10]

Answer:X=2

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Answer:

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Answer:

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