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3 years ago

Which expression has a value of 8?

Mathematics

2 answers:

Assoli18 [71]3 years ago

6 0

A.

4 + (4/4)x4 can be written as

4+ (1)x4 which is then

4+4, or 8

Bumek [7]3 years ago

6 0

None.

I don't see one that works

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A trail traveled 90 miles in 1.5 hours. At the same rate how long will it take the train to travel 330 miles

Arisa [49]

4.5 hours is 270 miles so just find out how long 60 miles takes and add that to 4.5 hours.

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3 years ago

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Find the values of x and y<br><br> 1-2i/ 2+i + 4-i/3+2i = x+iy

lina2011 [118]

Answer:

$x=\frac{10}{13}$ and $y=-\frac{24}{13}$

Step-by-step explanation:

The given complex number equation is:

$\frac{1-2i}{2+i}+\frac{4-i}{3+2i}=x+yi$

We simplify the LHS and compare with the RHS

We collect LCD on the left to get:

$\frac{(1-2i)(3+2i)+(4-i)(2+i)}{(2+i)(3+2i)}=x+yi$

$\frac{3+2i-6i+4+8+4i-2i+1}{6+4i+3i-2}=x+yi$

Simplify to get:

$\frac{16-2i}{4+7i}=x+yi$

Rationalize the LHS:

$\frac{(16-2i)(4-7i)}{(4+7i)(4-7i)}=x+yi$

Expand the numerator using the distributive property and the denominator using difference of two squares.

$\frac{64-112i-8i-14}{16+49}=x+yi$

Simplify to get:

$\frac{50-120i}{65}=x+yi$

$\frac{10-24i}{13}=x+yi$

$\frac{10}{13}-\frac{24}{13}i=x+yi$

By comparing real parts and imaginary parts; we have;

$x=\frac{10}{13}$ and $y=-\frac{24}{13}$

5 0

3 years ago

Find m<YQR pls need grade gud.

DaniilM [7]

Answer:

21°

Step-by-step explanation:

We can prove these two triangles congruent by the HL (Hypotenuse-Leg) theorem. Then, we know that m<YQR is congruent to m<PQY. We can then use their given values to form an equation.

5x+6=16x-27

Continue to solve . . .

33 = 11x

x=3

Therefore, we can plug this value of 3 into the expression for the value of m<YQR, and you will get

(16 x 3) - 27, which is equal to 21°.

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3 years ago

What are 12.95 mins 15.98

serg [7]

Answer:

-3.03

Step-by-step explanation:

12.95 - 15.98 = -3.03

Hope that helps!

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3 years ago

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EFGH is a rhombus. Given EG = 16 and FH = 12, what is the length of one side of the rhombus?

Black_prince [1.1K]

Answer:

Step-by-step explanation:

It is given that EFGH is a rhombus and EG = 16 and FH = 12.

We know that the diagonals of the rhombus are the perpendicular bisectors, therefore OF=6, OH=6, OE=8 and OG=8.

Now, using the Pythagoras theorem in ΔOFG, we have

$(FG)^{2}=(OG)^{2}+(OF)^{2}$

$(FG)^{2}=(8)^{2}+(6)^{2}$

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$FG=\sqrt{100}$

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Thus, the value of the side of the rhombus will be 10 units.

Hence, option C is correct.

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4 years ago

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