PLEAZE HELP IM FAILING THIS CLASS 9) The volume of a box is represented by x' +11x² + 20x – 32. The width of the box is x – 1, a
1 answer:
Answer:
Step-by-step explanation:
Volume of the box = x³ +11x² + 20x – 32 I think the ' is a typo for ³
the width is x-1 and the height is x+8
Find an expression for the length
Vol = LWH solve L
Vol / (WH) = L so
L = (x³ +11x² + 20x – 32) / (x-1) (x+8)
so it would help to factor the numerator
(x³ +11x² + 20x – 32) I'm willing to bet (x-1) and (x+8) are factors
but I will plot the equation to find the three roots
(x³ +11x² + 20x – 32) = (x-1) (x+8) (x+4)
L = (x³ +11x² + 20x – 32) / (x-1) (x+8)
= (x-1) (x+8) (x+4) / (x-1) (x+8) the (x-1) and (x+8) cancel out leaving
L = (x + 4)
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From the attached graphic:
e = c*h/wavelength therefore,
wavelength = c*h / e
wavelength = 299,792,458 * 6.62606957e-34 / 3.38x10^-19
wavelength = 5.8771e-7 meters
e = c*h/wavelength therefore,
wavelength = c*h / e
wavelength = 299,792,458 * 6.62606957e-34 / 3.38x10^-19
wavelength = 5.8771e-7 meters
Answer:
We see that the p value is higher than the ususal significance levels commonly used of 1% or 5% so then we can conclude that we FAIL to reject the null hypothesis, and there is not enough evidence to conclude that we have a different response between the two drugs
Step-by-step explanation:
We have the following info given by the problem
Subject 1 2 3 4 5 6 7
Drug A 6 3 4 5 7 1 4
Drug B 5 1 5 5 5 2 2
x=value for drug A , y = value for drug B
x: 6 3 4 5 7 1 4
y: 5 1 5 5 5 2 2
We want to verify if the mean response differs between the two drugs then the system of hypothesis for this case are:
Null hypothesis:
Alternative hypothesis:
We can begin calculating the difference and we obtain this:
d: -1, -2, 1, 0, -2, 1, -2
Now we can calculate the mean difference
Now we can find the the standard deviation for the differences, and we got:
And now we can calculate the statistic given by :
Now we can find the degrees of freedom given by:
We can calculate the p value, since we have a two tailed test the p value is given by:
We see that the p value is higher than the ususal significance levels commonly used of 1% or 5% so then we can conclude that we FAIL to reject the null hypothesis, and there is not enough evidence to conclude that we have a different response between the two drugs