Question

Find the equation of the straight line that passes through the points (1, 10) and (3, 2)

Answer 1

Answer:

2y + 8x = 28

Step-by-step explanation:

Hi there

So we are going to solve this together

m = y - y1/y2- y1 =x - x1/x2 - x1

y - 10/ 2- 10 =x - 1/ 3 -1

y -10/-8 =x - 1/2

cross multiply

2(y - 10) =-8(x -1)

2y - 20= -8x + 8

Collect terms

2y +8x = 8 +20

ANSWER = 2y + 8x = 28

Hope this helps you!

Bye , have a nice day :-)

Answer 2

Answer:

y = -4x + 14

Step-by-step explanation:

using the slope intercept form of a line

y = mx + c

Given points

• 1, 10
• 3, 2

slope (m) =

$= \frac{y2 - y1}{x2 - x1} \\ = \frac{2 - 10}{3 - 1} \\ = \frac{ - 8}{2} \\ = - 4$

taking one point as for filling x and y and finding the y intercept (c)

y =mx + c

10 = (-4) × 1 + c

10 + 4 = c

14 = c

therefore the equation is

y = -4x + 14