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zysi [14]
3 years ago
11

atex-formula">=?
Mathematics
2 answers:
xenn [34]3 years ago
5 0

Hello There

The answer is...

5.

HopeThisHelps!!

AnimeVines

galben [10]3 years ago
3 0
Hi the answer is 5 to this problem
Hope it helps.
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What is the length of the other diagonal DF?<br> 5 cm<br> 16 cm <br> 21 cm <br> 32 cm
frez [133]
To solve this you need to know Pythagorean theorem.

First, EG is 24, so the halfway points are 12. Knowing Pythagorean triples, you can use 5,12,13 and 12,16,20.

DF = 5+16
DF = 21

If you don't know Pythagorean triples, I have worked it out on the image attached.

3 0
3 years ago
Read 2 more answers
A 100 mL vial of 25% solution is available in stock. An order is recieved for 6 g to be added to 250 mL of fluid for an iv infus
Ne4ueva [31]

9514 1404 393

Answer:

  274 mL

Step-by-step explanation:

Often medical solutions expressed as a percentage are not really a percentage as such. A percentage is the ratio of two quantities with the same units.

Here, the context given by the problem suggests the "25%" solution is really (25 g)/(100 mL). That is, the units are grams and milliliters--different units.

With that assumption, we want to find the volume (v) of solution needed to deliver 6 g of medicine. An appropriate proportion* is ...

  v/(6 g) = (100 mL)/(25 g)

  v = (6 g)(100 mL)/(25 g) = 24 mL

So, the total volume of the infusion is ...

  250 mL +24 mL = 274 mL

_____

* The concentration is given in terms of g/mL, but we have used a proportion that is mL/g. The reason for that is we want the variable to be in the numerator of the ratio. The variable here represents volume, so we have written the proportion with volumes in the numerators.

Having the variable in the numerator means the equation can be solved in one step--by multiplying by its denominator.

3 0
3 years ago
A rock thrown vertically upward from the surface of the moon at a velocity of 36​m/sec reaches a height of s = 36t - 0.8 t^2 met
Verdich [7]

Answer:

a. The rock's velocity is v(t)=36-1.6t \:{(m/s)}  and the acceleration is a(t)=-1.6  \:{(m/s^2)}

b. It takes 22.5 seconds to reach the highest point.

c. The rock goes up to 405 m.

d. It reach half its maximum height when time is 6.59 s or 38.41 s.

e. The rock is aloft for 45 seconds.

Step-by-step explanation:

  • Velocity is defined as the rate of change of position or the rate of displacement. v(t)=\frac{ds}{dt}
  • Acceleration is defined as the rate of change of velocity. a(t)=\frac{dv}{dt}

a.

The rock's velocity is the derivative of the height function s(t) = 36t - 0.8 t^2

v(t)=\frac{d}{dt}(36t - 0.8 t^2) \\\\\mathrm{Apply\:the\:Sum/Difference\:Rule}:\quad \left(f\pm g\right)'=f\:'\pm g'\\\\v(t)=\frac{d}{dt}\left(36t\right)-\frac{d}{dt}\left(0.8t^2\right)\\\\v(t)=36-1.6t

The rock's acceleration is the derivative of the velocity function v(t)=36-1.6t

a(t)=\frac{d}{dt}(36-1.6t)\\\\a(t)=-1.6

b. The rock will reach its highest point when the velocity becomes zero.

v(t)=36-1.6t=0\\36\cdot \:10-1.6t\cdot \:10=0\cdot \:10\\360-16t=0\\360-16t-360=0-360\\-16t=-360\\t=\frac{45}{2}=22.5

It takes 22.5 seconds to reach the highest point.

c. The rock reach its highest point when t = 22.5 s

Thus

s(22.5) = 36(22.5) - 0.8 (22.5)^2\\s(22.5) =405

So the rock goes up to 405 m.

d. The maximum height is 405 m. So the half of its maximum height = \frac{405}{2} =202.5 \:m

To find the time it reach half its maximum height, we need to solve

36t - 0.8 t^2=202.5\\36t\cdot \:10-0.8t^2\cdot \:10=202.5\cdot \:10\\360t-8t^2=2025\\360t-8t^2-2025=2025-2025\\-8t^2+360t-2025=0

For a quadratic equation of the form ax^2+bx+c=0 the solutions are

x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\mathrm{For\:}\quad a=-8,\:b=360,\:c=-2025:\\\\t=\frac{-360+\sqrt{360^2-4\left(-8\right)\left(-2025\right)}}{2\left(-8\right)}=\frac{45\left(2-\sqrt{2}\right)}{4}\approx 6.59\\\\t=\frac{-360-\sqrt{360^2-4\left(-8\right)\left(-2025\right)}}{2\left(-8\right)}=\frac{45\left(2+\sqrt{2}\right)}{4}\approx 38.41

It reach half its maximum height when time is 6.59 s or 38.41 s.

e. It is aloft until s(t) = 0 again

36t - 0.8 t^2=0\\\\\mathrm{Factor\:}36t-0.8t^2\rightarrow -t\left(0.8t-36\right)\\\\\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}\\\\t=0,\:t=45

The rock is aloft for 45 seconds.

5 0
3 years ago
The vertex form of the equation of a parabola is y = 2(x + 3)2 - 5. What is the standard form of the equation?
svet-max [94.6K]
Hello : 
<span>y = 2(x + 3)² - 5
y = 2(x²+6x+9) -5
y = 2x² +12x +13...(answer : </span><span>A) y=2x^2+12x+13 )</span>
7 0
3 years ago
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How do you do equivalent fractions ?
USPshnik [31]
They are equal fractions that go into each other. for example, 
2/4 goes into 4/8
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