All categories

3 years ago

Can someone plz help meee

Mathematics

1 answer:

Naya [18.7K]3 years ago

6 0

Answer:

$\sqrt{144}$

Step-by-step explanation:

$15^{2}$ = $x^{2} + 9^{2}$

$x^{2} = 15^{2} - 9^{2} \\x^{2} = 144\\x = \sqrt{144}$

You might be interested in

Write 1.68 as a percent.

Ray Of Light [21]

Answer:

1.68 as a percent is 168%.

Step-by-step explanation:

To convert 1.68 to a percentage, multiply the number 1.68 by 100.

4 0

3 years ago

Read 2 more answers

What is the eqation of M <br> What is the equation of N

defon

Answer:

m is the slope but n I don't know sorry

7 0

3 years ago

In the figure, what is the value of x?

maks197457 [2]

Answer:x=90 °

Step-by-step explanation:

In any circle the exterior angle formed is half of the major arc - minor arc .

Angle formed by tangents or secants = $\frac{1}{2}(Major arc - minor arc )$

The sum of measure of arcs inany circle is 360°.

Minor arc is given as x°.So Major arc = 360-x.

Substituting the given values in the formula :

$x=\frac{1}{2}(360-x-x)$

$x=\frac{1}{2}(360-2x)$

x=180-x

Adding x both sides we have:

2x=180.

Dividing both sides by 2.x= 90.

8 0

3 years ago

Read 2 more answers

The geometic mean of 4 and 21

-Dominant- [34]

Answer:

12.5

Step-by-step explanation:

4+21=25

25/2=12.5

4 0

3 years ago

You have received an order of 100 robotic resistance spot welders which contains 5 defective welders. You randomly select 15 wel

erica [24]

Answer:

$P(X = 0) = h(0,100,15,5) = \frac{C_{5,0}*C_{95,15}}{C_{100,15}} = 0.4357$

$P(X = 1) = h(1,100,15,5) = \frac{C_{5,1}*C_{95,14}}{C_{100,15}} = 0.4034$

$P(X = 2) = h(2,100,15,5) = \frac{C_{5,2}*C_{95,13}}{C_{100,15}} = 0.1377$

$P(X = 3) = h(3,100,15,5) = \frac{C_{5,3}*C_{95,12}}{C_{100,15}} = 0.0216$

$P(X = 4) = h(4,100,15,5) = \frac{C_{5,4}*C_{95,11}}{C_{100,15}} = 0.0015$

$P(X = 5) = h(5,100,15,5) = \frac{C_{5,5}*C_{95,10}}{C_{100,15}} = 0.00004$

b) 0.154% probability that there are at least 4 defective welders in the sample

Step-by-step explanation:

The welders are chosen without replacement, so the hypergeometric distribution is used.

The probability of x sucesses is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question:

100 welders, so $N = 100$

Sample of 15, so $n = 15$

In total, 5 defective, so $k = 5$

(a) Determine the PMF of the number of defective welders in your sample?

There are 5 defective, so this is P(X = 0) to P(X = 5). Then

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 0) = h(0,100,15,5) = \frac{C_{5,0}*C_{95,15}}{C_{100,15}} = 0.4357$

$P(X = 1) = h(1,100,15,5) = \frac{C_{5,1}*C_{95,14}}{C_{100,15}} = 0.4034$

$P(X = 2) = h(2,100,15,5) = \frac{C_{5,2}*C_{95,13}}{C_{100,15}} = 0.1377$

$P(X = 3) = h(3,100,15,5) = \frac{C_{5,3}*C_{95,12}}{C_{100,15}} = 0.0216$

$P(X = 4) = h(4,100,15,5) = \frac{C_{5,4}*C_{95,11}}{C_{100,15}} = 0.0015$

$P(X = 5) = h(5,100,15,5) = \frac{C_{5,5}*C_{95,10}}{C_{100,15}} = 0.00004$

(b) Determine the probability that there are at least 4 defective welders in the sample?

$P(X \geq 4) = P(X = 4) + P(X = 5) = 0.0015 + 0.00004 = 0.00154$

0.154% probability that there are at least 4 defective welders in the sample

5 0

3 years ago