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scoundrel [369]
3 years ago
14

the vertex of this parabola is at (2,-4). when the y-value us -3, the x-value is -3. what is the coefficient of the squared term

in the parabolas equation?​
Mathematics
2 answers:
tatyana61 [14]3 years ago
8 0

Answer:

-5

Step-by-step explanation:

from a p e x

alex41 [277]3 years ago
3 0

Answer:

The coefficient of the squared term is 1/25.

Step-by-step explanation:

We are given that the vertex of a parabola is at (2, -4). We also know that <em>y</em> = -3 when <em>x</em> = -3.

And we want to determine the coefficient of the squared term of the equation.

Since we are given the vertex, we can use the vertex form of the quadratic:

\displaystyle y = a(x-h)^2+k

Where (<em>h, k</em>) is the vertex and <em>a</em> is the leading coefficient. The leading coefficient is also the coefficient of the squared term, so we simply need to find the value of <em>a</em>.

Since the vertex is at (2, -4), <em>h</em> = 2 and <em>k</em> = -4. Substitute:

\displaystyle y = a(x-2)^2-4

<em>y</em> = -3 when <em>x</em> = -3. Solve for <em>a</em>:

\displaystyle (-3) = a((-3)-2)^2-4

Simplify:

\displaystyle 1 = a(-5)^2\Rightarrow a = \frac{1}{25}

Therefore, our function in vertex form is:

\displaystyle f(x) = \frac{1}{25}\left(x-2)^2-4

Hence, the coefficient of the squared term is 1/25.

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