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Fynjy0 [20]
3 years ago
14

Which of the following equations have complex roots?

Mathematics
1 answer:
goldenfox [79]3 years ago
6 0

9514 1404 393

Answer:

  B.  3x² +2 = 0

Step-by-step explanation:

The equation of A has a couple of real roots. We're pretty sure there are complex numbers that will satisfy this equation, but we don't know how to find them. (We suspect a typo, and that the equation is supposed to be 2x² +1 = 7x, which has only real roots.)

__

The equation of B can be rewritten as ...

  x² = -2/3

This will have complex roots.

__

The discriminants of both equations C and D are positive, so those have only real roots.

  2x² -5x -1   ⇒   d = (-5)² -4(2)(-1) = 33

  3x² -6x -1   ⇒   d = (-6)² -4(3)(-1) = 48

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Solve the following problems:
guajiro [1.7K]

Answer:

100 and 120

Step-by-step explanation:

I might be wrong but there were no answers

3 0
3 years ago
An astronaut on the moon throws a baseball upward. The astronaut is 6 ft 6 in tall, and the initial velocity of the ball is 40 f
weqwewe [10]

Answer:

t = 0.293 s and 14.52 s

Step-by-step explanation:

The heights of the ball in feet is given by the equation as follows :

S = -2.7t^2+40t+6.5

Where t is the number of seconds after the ball was thrown.

We need to find is the ball 18 ft above the moon's surface.

Put S = 18 ft

-2.7t^2+40t+6.5=18\\\\-2.7t^2+40t=18-6.5\\\\-2.7t^2+40t-11.5=0

It is a quadratic equation. Its solution is given by :

t=\dfrac{-40+\sqrt{40^{2\ }-4\left(-2.7\right)\left(-11.5\right)}}{2\left(-2.7\right)},\dfrac{-40-\sqrt{40^{2\ }-4\left(-2.7\right)\left(-11.5\right)}}{2\left(-2.7\right)}\\\\t=0.293\ s,14.52\ s

So, the ball is at first 0.293 s and then 14.52 s above the Moon's surface.

8 0
3 years ago
What is the simplified form of each expression?
White raven [17]
<h2>~<u>Solution</u> :-</h2>

According to the given question, we have to find the simplified form of the given expressions. Here, we have been given;

<h3>★ <u>Equation</u> 1 :-</h3>

\sf{(6 + 3)2 - 4}

\leadsto \sf{(9)2 - 4}

\leadsto \sf{18 - 4}

\leadsto \bf \red{14}

  • Hence, (6 + 3)2 - 4 is equals to 14.

\\

<h3>★ <u>Equation</u> 2 :-</h3>

\sf{23 + (14 - 4) \div 2}

\leadsto \sf{23 + (10) \div 2}

\leadsto \sf{23 + 5}

\leadsto \bf \red{28}

  • Hence, 23 + (14 - 4) ÷ 2 is equals to 28.

\\  \\  \\

#LemmieFeel

6 0
3 years ago
Read 2 more answers
ative section 3. a) The angle of elevation of the top of a tree observed from a point 60 m away from its foot is 45. Find the he
Zigmanuir [339]

Answer:

The height of the tree is is 60m

Step-by-step explanation:

Let's answer a, as it is the only complete question.

We know that the angle of elevation of the top of a tree observed from a point 60m away, is 45°.

We can model this with a triangle rectangle, a sketch of it can be seen below (assuming that you are looking it from the ground).

You can see that the adjacent cathetus to the 45° angle is equal to 60m

And the opposite cathetus is the measure we want to find.

Now you can remember the trigonometric relation:

tan(a) = (opposite cathetus)/(adjacent cathetus).

So to find the height of the tree we need to solve:

tan(45°) = H/60m

This is just:

tan(45°)*60m = H  =60m

The height of the tree is is 60m

3 0
3 years ago
Given m
Ronch [10]

Answer:

x + 80°= 180° ( angles made in straight line)

x = 180°-80°

x = 100°

hope it is helpful to you

6 0
3 years ago
Read 2 more answers
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