Please use a ruler I will give you points

David charges $4 to wash all the windows of a car, inside and out. The amount of money he earns washing the windows must end in

nordsb [41]

Answer:

The possible digits are : 0, 2, 6, 4, 8

Step-by-step explanation:

Money charged by David to wash the windows of a car = $4

Let total number of cars he washed be x

Now, Total money earned by washing windows of a car = Money charged for washing all windows of one car × Total number of cars washed

⇒ Total money earned = 4 × x

So, the amount will always end in the digits which comes at the end of multiples of 4 because the amount will be always in the multiples of 4

⇒ 4 × 1 = 4 , 4 × 2 = 8 , 4 × 3 = 12 , 4 × 4 = 16 , 4 × 5 = 20 ......

So, the possible digits are : 0, 2, 6, 4, 8

4 0

4 years ago

12+(8x(4+3)+2)-6 evaluate the expression

Slav-nsk [51]

Let's simplify step-by-step.12+8x(4+3)+2−6=12+56x+2+−6

Combine Like Terms:=12+56x+2+−6=(56x)+(12+2+−6)=56x+8

Answer:=56x+8

Good luck mate :P

5 0

3 years ago

Read 2 more answers

I just cant remember how to do these ones. been so long Solve 2x – 5 = 7

TEA [102]

Answer:

2x=7+5

2x=12

X=12/2=6

Kskwkjxu

8 0

3 years ago

A union of restaurant and foodservice workers would like to estimate the mean hourly wage, μ, of foodservice workers in the U.S.

pav-90 [236]

Answer:

$n=(\frac{1.960(2.25)}{0.35})^2 =158.76 \approx 159$

So the answer for this case would be n=159 rounded up to the nearest integer

Step-by-step explanation:

Assuming this complete question: A union of restaurant and foodservice workers would like to estimate the mean hourly wage, , of foodservice workers in the U.S. The union will choose a random sample of wages and then estimate using the mean of the sample. What is the minimum sample size needed in order for the union to be 95% confident that its estimate is within $0.35 of ? Suppose that the standard deviation of wages of foodservice workers in the U.S. is about $2.15 .

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

$\sigma=2.25$ represent the population standard deviation

n represent the sample size

Solution to the problem

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{s}{\sqrt{n}}$ (a)

And on this case we have that ME =0.35 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

The critical value for 95% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.025;0;1)", and we got $z_{\alpha/2}=1.960$ , replacing into formula (b) we got:

$n=(\frac{1.960(2.25)}{0.35})^2 =158.76 \approx 159$

So the answer for this case would be n=159 rounded up to the nearest integer

3 0

3 years ago

HELP ME PRETTY PLEASE (WILL PICK BRAINLIEST ANSWER)

barxatty [35]

Answer:

An infinite number of solutions

Step-by-step explanation:

This is because of all the 0's the zeros represent none and none is infinite. When in the matrix you are solving and solving is a infinite. When times 0 is 0 and when divided by 0 is infinite so an infinite amount of answers.

6 0

3 years ago