Answer:
a) 0.9
b) Mean = 1.58
Standard Deviation = 0.89
Step-by-step explanation:
We are given the following in the question:
A marketing firm is considering making up to three new hires.
Let X be the variable describing the number of hiring in the company.
Thus, x can take values 0,1 ,2 and 3.
a) P(firm will make at least one hire)
Also,
b) expected value and the standard deviation of the number of hires.
![E(x^2) = \displaystyle\sum x_i^2P(x_i)\\=0(0.1) + 1(0.4) + 4(0.32) +9(0.18) = 3.3\\V(x) = E(x^2)-[E(x)]^2 = 3.3-(1.58)^2 = 0.80\\\text{Standard Deviation} = \sqrt{V(x)} = \sqrt{0.8036} = 0.89](https://tex.z-dn.net/?f=E%28x%5E2%29%20%3D%20%5Cdisplaystyle%5Csum%20x_i%5E2P%28x_i%29%5C%5C%3D0%280.1%29%20%2B%201%280.4%29%20%2B%204%280.32%29%20%2B9%280.18%29%20%3D%203.3%5C%5CV%28x%29%20%3D%20E%28x%5E2%29-%5BE%28x%29%5D%5E2%20%3D%203.3-%281.58%29%5E2%20%3D%200.80%5C%5C%5Ctext%7BStandard%20Deviation%7D%20%3D%20%5Csqrt%7BV%28x%29%7D%20%3D%20%5Csqrt%7B0.8036%7D%20%3D%200.89)
First you divide 39/40
you would get 0.975
<h3>Answer:</h3>
$808.38
<h3>Explanation:</h3>
The formula for the payment amount (A) on principal P at interest rate r compounded monthly for a loan period of t years is ...
... A = P(r/12)/(1 -(1 +r/12)^(-12t))
For the main loan, the payment is ...
... A = 0.80·145000·(.0475/12)/(1 -(1 +.0475/12)^(-12·30)) = 605.11
For the piggyback loan, the payment is ...
... A = 0.20·145000·(.07525/12)/(1 -(1 +.07525/12)^(-12·30)) = 203.27
So, the total of monthly payments for the two loans is ...
... $605.11 +203.27 = $808.38
Answer:
Step-by-step explanation:
1000 - 10% = 900
Answer:
<2 and <3
Step-by-step explanation:
Given that lines l and m are parallel to each other, and crossed by the transversal line t, the angles formed that are supplementary to <1 are <2 and <3.
<1 and <2 are linear pair. Their sum equal 180°.
<1 and <2 are also a linear pair. Their sum equal 180°.
Therefore, that are supplementary to <1 are <2 and <3.
