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Alexxx [7]
3 years ago
8

HowSolve The D. E dy/dx=2x^5 y^3 - 4y/x​

Mathematics
1 answer:
Pachacha [2.7K]3 years ago
3 0
Dy/dx (2x⁵ y³ - 4y/x)

dy/dx (2y³ x⁵ - 4y/x)

dy/dx ( 2y³ x⁵ ) - dy/dx (4y/x)

= 2y³ 5x⁴ - (-4y × 1/x²)

=
10x⁶ y³ + 4y
-------------------
x²

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Help subtract (xsquared +43x10)-(10xsquared-5x+10 express the answer in standard form
ad-work [718]

Answer:

\large\boxed{(x^2+43x+10)-(10x^2-5x+10)=-9x^2+48x}

Step-by-step explanation:

(x^2+43x+10)-(10x^2-5x+10)\\\\=x^2+43x+10-10x^2-(-5x)-10\\\\=x^2+43x+10-10x^2+5x-10\qquad\text{combine like terms}\\\\=(x^2-10x^2)+(43x+5x)+(10-10)\\\\=-9x^2+48x

6 0
3 years ago
PLEASE HELP AS SOON AS POSSIBLE
frutty [35]

Answer:

FALSE

TRUE

TRUE

Step-by-step explanation:

For median,

Arrange your numbers in numerical order.

Count how many numbers you have.

If you have an odd number, divide by 2 and round up to get the position of the median number.

If you have an even number, divide by 2. Go to the number in that position and average it with the number in the next higher position to get the median.

Source: https://www.verywellmind.com/how-to-identify-and-calculate-the-mean-median-or-mode-2795785

So for April median: 2.5, 3, 3.5, 3.5 (since we have 4 numbers we divide by 2 and we count by 2 places from left. Since we have even number data, we average 3 with the next higher position to get the median so (3+3.5)/2 = 3.25

For May apply same concept and you get median to be 2.25.

Median difference is 3.25-2.25 = 1

Therefore, statement 1 is false and statement 2 is true.

For average in May, add all numbers and divide by the number of data points so May= (2.5+3+3.5+3.5)/ 4 = 3.13

Apply same concept you for April and you get 2.38 as mean.

Mean difference is 3.13-2.38 = 0.75

Therefore, statement 3 is correct (true)

4 0
3 years ago
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