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2 years ago

HowSolve The D. E dy/dx=2x^5 y^3 - 4y/x

1 answer:

3 0

Dy/dx (2x⁵ y³ - 4y/x)

dy/dx (2y³ x⁵ - 4y/x)

dy/dx ( 2y³ x⁵ ) - dy/dx (4y/x)

= 2y³ 5x⁴ - (-4y × 1/x²)

=
10x⁶ y³ + 4y
-------------------
x²

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1 year ago

The level of nitrogen oxides (NOX) in the exhaust after 50,000 miles or fewer of driving of cars of a particular model varies No

Greeley [361]

Answer:

For a level of 0.0174 or more of nitrogen oxide, the probability of fleet is 0.01.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 0.02 g/mi

Standard Deviation, σ = 0.01 g/mi

Sample size, n = 81

We are given that the distribution of level of nitrogen oxides is a bell shaped distribution that is a normal distribution.

Standard error due to sampling:

$=\dfrac{\sigma}{\sqrt{n}} = \dfrac{0.01}{\sqrt{81}} = 0.0011$

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

We have to find the value of x such that the probability is 0.01

P(X > x)

$P( X > x) = P( z > \displaystyle\frac{x - 0.02}{0.0011})=0.01$

$= 1 -P( z \leq \displaystyle\frac{x - 0.02}{0.0011})=0.01$

$=P( z \leq \displaystyle\frac{x - 0.02}{0.0011})=0.99$

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2 years ago

I need help with 63 64 and 65 please please please help

snow_tiger [21]

#64
Let x represent the time spent for valleyball
Then swimming will be 2x

x + 2x = 4.5
3x = 4.5
x = 4.5/3
x = 1.5

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Time spent on swimming: 3 hours

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3 years ago

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3 years ago

Number 5 am stuck pls help

Norma-Jean [14]

Answer:

im going to be honest i havent done this since las year and so i dont remember the value of that line outside but i think its 70*

Step-by-step explanation:

reason is because the c is originally 180* but it has more of and angle so the angles obv increases and you can get the angle by multiplying 70*times 7x and divide by 3

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2 years ago

HowSolve The D. E dy/dx=2x^5 y^3 - 4y/x​

HowSolve The D. E dy/dx=2x^5 y^3 - 4y/x