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Afina-wow [57]
3 years ago
12

Plssss I need help Im in classsss plsss

Mathematics
1 answer:
Sav [38]3 years ago
5 0

Step-by-step explanation:

Y=-4x+3

2x+3y=19

2x+3(-4x+3)=19

2x-12x+9=19

-10x=10

X=-1

y=-4*(-1)+3=4+3=7

x=-1 y=7

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Mot gonna say anything anymore but uh yeah
melamori03 [73]

Answer:

x=5

Step-by-step explanation:

5x-3=4x+2

x-3=2

x=5

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What is the smallest positive integer whose proper divisors add up to more than the integer itself?
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I pretty sure it's 1
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4 years ago
Suppose that the members of a student governance committee will be selected from the 40 members of the student senate. There are
Len [333]

Answer:

The total number of ways to form a student governance committee is 1,211,760.

Step-by-step explanation:

The students senate consists of a total of 40 students.

The students are either Sophomores or Juniors or Seniors.

The number of students in each of these categories are as follows:

Sophomores = 18

Juniors = 12

Seniors = 10

A governance committee have to be selected from the students senate.

The committee have to made up of 2 sophomores, 2 juniors and 3 seniors.

Combinations can be used to select 2 sophomores from 18, 2 juniors from 12 and 3 seniors from 10.

Combinations is a mathematical technique used to determine the number of ways to select <em>k</em> items from <em>n</em> distinct items.

The formula is:

{n\choose k}=\frac{n!}{k!(n-k)!}

(1)

Compute the number of ways to select 2 sophomores from 18 as follows:

{n\choose k}=\frac{n!}{k!(n-k)!}

{18\choose 2}=\frac{18!}{2!(18-2)!}=\frac{18\times 17\times 16!}{2\times 16!}=153

Thus, there are 153 ways to select 2 sophomores from 18.

(2)

Compute the number of ways to select 2 juniors from 12 as follows:

{n\choose k}=\frac{n!}{k!(n-k)!}

{12\choose 2}=\frac{12!}{2!(12-2)!}=\frac{12\times 11\times 10!}{2\times 10!}=66

Thus, there are 66 ways to select 2 juniors from 12.

(3)

Compute the number of ways to select 3 seniors from 10 as follows:

{n\choose k}=\frac{n!}{k!(n-k)!}

{10\choose 3}=\frac{10!}{3!(10-3)!}=\frac{10\times 9\times 8\times 7!}{2\times 3\times 7!}=120

Thus, there are 120 ways to select 3 seniors from 10.

The total number of ways to form a student governance committee that must have 2 sophomores, 2 juniors and 3 seniors is:

Total number of ways = {18\choose 2}\times {12\choose 2}\times {10\choose 3}

                                    =153\times 66\times 120\\=1211760

Thus, the total number of ways to form a student governance committee is 1,211,760.

7 0
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A toy's store percent of markup is 35%.a model train costs 100$.what is the markup
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Markup =35%
Model train cost =100
So 135%=100
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