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hoa [83]
3 years ago
9

Is the sequence below is arithmetic {1, 8, 27,64}

Mathematics
1 answer:
Rzqust [24]3 years ago
6 0

Answer:

No

Step-by-step explanation:

No, because 8 - 1 ≠ 27 - 8. So, there is no common difference which is needed in order for the sequence to be arithmetic

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(8.4x + 2.9) + (-3.7x + 5).
konstantin123 [22]

Answer:

10

Step-by-step explanation:

4 0
4 years ago
Your friend earns $10.50 per hour this is 125% of her hourly wage last year how much did your friend make last year
NNADVOKAT [17]
10.50/5=2.10
2.10*4=8.40
She used to earn $8.50/hr
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3 years ago
225 g flour
Pachacha [2.7K]
If she needs to use 225g of flour for each cake and wants to make 18 cakes she will need 4050g (225x18=4050) of flour but she only has 360g which is obviously not enough flour. For one cake she needs 75g of sugar and since she needs to make 18 cakes she needs 1350g (75x18=1350) of sugar. She only has 135g so it’s not enough.
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3 years ago
What is the minimum number of bits required to store each binary string of length 50? (b) what is the minimum number of bits req
antiseptic1488 [7]
In order to answer the above question, you should know the general rule to solve these questions.
The general rule states that there are 2ⁿ subsets of a set with n number of elements and we can use the logarithmic function to get the required number of bits.
That is: 
log₂(2ⁿ) = n number of <span>bits
</span>
a). <span>What is the minimum number of bits required to store each binary string of length 50?
</span>
Answer: In this situation, we have n = 50. Therefore,  2⁵⁰ binary strings of length 50 are there and so it would require:

                                                     log₂(2⁵⁰) <span>= 50 bits.

b). </span><span>what is the minimum number of bits required to store each number with 9 base of ten digits?
</span>
Answer: In this situation, we have n = 50. Therefore, 10⁹ numbers with 9 base ten digits are there and so it would require:

                                                     log2(109)= 29.89 
<span>                                                                     = 30 bits. (rounded to the nearest                                                                                                                        whole #)

c).  </span><span>what is the minimum number of bits required to store each length 10 fixed-density binary string with 4 ones?
</span>
Answer: There is (10,4) length 10 fixed density binary strings with 4 ones and
so it would require:
                                                     log₂(10,4)=log₂(210) = 7.7
                                                                    = 8 bits. (rounded to the nearest                                                                                                                        whole #)
4 0
3 years ago
The image of a dust mite from a scanning electron microscope is 1.5×10 to the 2nd millimeters wide. The image is 5×10 to 2nd tim
Vinil7 [7]
600 millimeters is the accuracy
7 0
3 years ago
Read 2 more answers
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