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2 years ago

Removing this account, any words

Mathematics

2 answers:

iVinArrow [24]2 years ago

7 0

Answer:

Thanks for the free points. Sayonara, mate.

Step-by-step explanation:

My name is Ann [436]2 years ago

4 0

Answer: Cya

Step-by-step explanation:

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Ms. Warren had each student take 3 pencils and create a triangle with them. Roberto has 3 pencils that measure 12 cm, 5 cm, and

cestrela7 [59]

Answer:

One.

Step-by-step explanation:

The reason why is because 12-5 = 7, meaning that your lowest length has to be 7. meaning, that you can only do one triangle.

7 0

2 years ago

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Which shape is a rectangle

Nezavi [6.7K]

Answer:

Top left.

Step-by-step explanation:

Definition of a rectangle:

A four sided figure with 90 degree angles. The opposing side pairs are congruent with each other. It's the equivalent of a modified, upgraded parallelogram.

Now, the square is the answer since it fits all of the criteria of the rectangle, with the addition of having four congruent sides.

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2 years ago

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7 2 − 140 degrees for angles

pickupchik [31]

Answer:

What?

Step-by-step explanation:

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1 year ago

The graph of an inverse trigonometric function passes through the point (1, pi/2). Which of the following could be the equation

rodikova [14]

Answer: C) $y=sin^-1 x$

Step-by-step explanation:

Since, the graph of an inverse trigonometric function will pass through the point $(1,\frac{\pi}{2})$ ,

If this point satisfies the function,

For the function $y=cos^{-1} x$

If x = 1

$y=cos^{-1}1=0$

Thus, $(1,\frac{\pi}{2})$ is not satisfying function $y=cos^{-1} x$ ,

⇒ The graph of $y=cos^{-1} x$ is not passing through the point $(1,\frac{\pi}{2})$

For the function $y=cot^{-1}x$

If x = 1

$y=cot^{-1}1=\frac{\pi}{4}$

Thus, $(1,\frac{\pi}{2})$ is not satisfying function $y=cot^{-1}x$ ,

⇒ The graph of $y=cot^{-1}x$ is not passing through the point $(1,\frac{\pi}{2})$

For the function $y=sin^{-1} x$

If x = 1

$y=sin^{-1}1=\frac{\pi}{2}$

Thus, $(1,\frac{\pi}{2})$ is satisfying function $y=sin^{-1} x$ ,

⇒ The graph of $y=sin^{-1} x$ is passing through the point $(1,\frac{\pi}{2})$ .

For the function $y=tan^{-1}x$

If x = 1

$y=tan^{-1}1=\frac{\pi}{4}$

Thus, $(1,\frac{\pi}{2})$ is not satisfying function $y=cos^{-1} x$ ,

⇒ The graph of $y=tan^{-1} x$ is not passing through the point $(1,\frac{\pi}{2})$ .

Hence, Option C is correct.

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2 years ago

Help ill give brainlest pls

Citrus2011 [14]

Answer:

It is A

Step-by-step explanation:

Cuz it rotates Over the axis and reflect over it

8 0

1 year ago

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