1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ollegr [7]
3 years ago
10

How do you find the answer for 7(x-5)²=63

Mathematics
1 answer:
zepelin [54]3 years ago
8 0

Answer:

Step-by-step explanation:

7(x-5)²=63

(x-5)²=63/7

\sqrt{ (x-5)^{2} } = \sqrt9 }

(x-5) = +/- 3

x = 5 + 3

or

x = 5- 3

x = 8 or 2

You might be interested in
Write an expression which solves for the radius of an object having the circumference of 30 feet
Likurg_2 [28]
circumference=30ft.\\\\circumference=2\pi r\ (r-radius)\\\\2\pi r=30\ \ \ \ /:2\pi\\\\r=\frac{30}{2\pi}\\\\r=\frac{15}{\pi}\ (ft)\\\\\frac{15}{\pi}\approx\frac{15}{3.14}\approx4.78\ (ft)
8 0
3 years ago
Read 2 more answers
Medical scientists study the effect of acute infection on tissue-specific immunity. In a collection of experiments under the sam
Serjik [45]

Answer:

The 95% confidence interval  for the true proportion of mice that will test positive under similar conditions is (0.5291, 0.6429).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence interval 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

Z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

In a collection of experiments under the same conditions, 44 of 75 mice test positive for lymphadenopathy. This means that n = 75 and \pi = \frac{44}{75} = 0.586.

Compute a 95% confidence interval for the true proportion of mice that will test positive under similar conditions.

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.586 - 1.96\sqrt{\frac{0.586*0.414}{75}} = 0.5291

The upper limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.586 + 1.96\sqrt{\frac{0.586*0.414}{75}} = 0.6429

The 95% confidence interval  for the true proportion of mice that will test positive under similar conditions is (0.5291, 0.6429).

7 0
3 years ago
Is the equation 8 + 4= -5 + 7 true false or open and why
zysi [14]
This is false, because the equation is then 12=2, which is incorrect.

Hope this helps!

~ThePirc
4 0
3 years ago
Read 2 more answers
Which Situation has a greater Rate of Change?<br> A: f(x) = 2(5)*<br> B: f() = 5(2)
Ivanshal [37]

Answer:

B

Step-by-step explanation:

Since 2 is the constant on A and 5 on B and 5's multiples are greater then 2's

7 0
3 years ago
Given that f(x) = x2 - 16 and g(x) = 20 - x, find (f-g)-4),
zavuch27 [327]

( {x}^{2}  - 16) - (20 - x) - 4  \\ =  {x}^{2}  + x - 40

4 0
2 years ago
Other questions:
  • Rover’s dog bowl is pictured below. Approximately how much water does it hold? Use 3.14 for π and round your answer to the neare
    13·1 answer
  • What is 7 (1+10p) + 8 (1 + 6p)
    9·2 answers
  • The expression 3xy-(2x+4xy) is equivalent to
    12·1 answer
  • Which of the following lists the numbers shown above in order from greatest to least?
    13·1 answer
  • Which of the following statements is not true of deductive reasoning?
    10·1 answer
  • Help me please it's easy ig
    5·1 answer
  • Beyunka has six baseballs that she keeps at her grandparents’ house. That number represents 20% of the baseballs that come in a
    9·1 answer
  • Suppose that IQ scores have a bell-shaped distribution with a mean of 105 and a standard deviation of 15. Using the empirical ru
    10·1 answer
  • Christina says the graph for the inequality r &lt; -5 will be the same as the graph for the inequality -5 &gt; r. Do you agree o
    7·1 answer
  • Thank you for your help. The question is in the screenshot
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!