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Gwar [14]
3 years ago
8

In a diagram which of the following statements are false

Mathematics
1 answer:
lisabon 2012 [21]3 years ago
8 0

Answer:

i think ur answer would be the second one

Step-by-step explanation:

hope this helps!

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A representative from the National Football League's Marketing Division randomly selects people on a random street in Kansas Cit
Orlov [11]

Using the binomial distribution, we have that:

a) 0.1024 = 10.24% probability that the marketing representative must select 4 people to find one who attended the last home football game.

b) 0.2621 = 26.21% probability that the marketing representative must select more than 6 people to find one who attended the last home football game.

c) The expected number of people is 4, with a variance of 20.

For each person, there are only two possible outcomes. Either they attended a game, or they did not. The probability of a person attending a game is independent of any other person, which means that the binomial distribution is used.

Binomial probability distribution  

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}  

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • p is the probability of a success on a single trial.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

The expected number of <u>trials before q successes</u> is given by:

E = \frac{q(1-p)}{p}

The variance is:

V = \frac{q(1-p)}{p^2}

In this problem, 0.2 probability of a finding a person who attended the last football game, thus p = 0.2.

Item a:

  • None of the first three attended, which is P(X = 0) when n = 3.
  • Fourth attended, with 0.2 probability.

Thus:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{3,0}.(0.2)^{0}.(0.8)^{3} = 0.512

0.2(0.512) = 0.1024

0.1024 = 10.24% probability that the marketing representative must select 4 people to find one who attended the last home football game.

Item b:

This is the probability that none of the first six went, which is P(X = 0) when n = 6.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{6,0}.(0.2)^{0}.(0.8)^{6} = 0.2621

0.2621 = 26.21% probability that the marketing representative must select more than 6 people to find one who attended the last home football game.

Item c:

  • One person, thus q = 1.

The expected value is:

E = \frac{q(1-p)}{p} = \frac{0.8}{0.2} = 4

The variance is:

V = \frac{0.8}{0.04} = 20

The expected number of people is 4, with a variance of 20.

A similar problem is given at brainly.com/question/24756209

3 0
1 year ago
Brainliest* and show work and the answer to number 15
barxatty [35]

Step-by-step explanation:

perimeter of semicircle=πr+2r

\frac{22}{7}  \times 1 + 2 \:  \:  \:  \:  \:  \:  \: (d = 2r)  \:  \\  \\ 5.14ft \:  \:  \:  \:  \:  \:  \:  \:

4 0
2 years ago
What are two events helped bring the renaissance?
vaieri [72.5K]

Answer:

The two major events that helped bring about the Renaissance were the Black Death and the development of banking systems

Step-by-step explanation:


5 0
3 years ago
3. A boat is travelling from Point C toward Point D, which is on the shoreline.
Firlakuza [10]

Answer:

Yes, lines CD & AB are perpendicular

Step-by-step explanation:

AB slope: y = -12/8x + 7

CD slope: y = 6/9x - 6

Once the slopes are simplified:

AB: -3/2

CD: 2/3

Hope this helps!

3 0
3 years ago
3) Two cars leave Cincinnati at the same time. Car A moves East at a constant speed of 60 miles per hour, while car B
Inessa [10]

Answer:

D). 262.5 miles.

Step-by-step explanation:

The speed at which they are drawing apart = 60 + 45 = 105 mph.

So in 2.5 hours they wiil be

2.5 * 105

= 210 + 52.5

= 262.5 miles.

4 0
2 years ago
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