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Gwar [14]
3 years ago
8

In a diagram which of the following statements are false

Mathematics
1 answer:
lisabon 2012 [21]3 years ago
8 0

Answer:

i think ur answer would be the second one

Step-by-step explanation:

hope this helps!

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Which statement about the cylinder are true? Select two options
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Answer:

\ur \: answer)

Step-by-step explanation:

<h2><em><u>THE</u></em><em><u> </u></em><em><u>RÅDIÜS</u></em><em><u> </u></em><em><u>ØF</u></em><em><u> </u></em><em><u>THE</u></em><em><u> </u></em><em><u>CYLI</u></em><em><u>NDER</u></em><em><u> IS</u></em></h2><h2><em><u>\frac{1}{2} x \: units</u></em></h2>

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5 0
3 years ago
Mario collected data about some of the players on a women’s basketball team. The data is shown in the form of table, mapping, an
Mumz [18]

Answer:

1. No, because each x value can only have one y value (one-to-one relationship).

2. No, because each x value can only have one y value (one-to-one relationship).

3. Yes, because one member of the domain is assigned to one member of the range.

Step-by-step explanation:

4 0
2 years ago
Suppose today is Tuesday. What day of the week will it be 100 days from now?
VladimirAG [237]
Sunday
Hope this helps!
7 0
4 years ago
For what value of the constant c is the function fcontinuous on (−[infinity], [infinity])?
Arlecino [84]

Answer:

For c=\frac{1}{7} the function f(x) is continuous on (-\infty,\infty).

Step-by-step explanation:

We have the following function

f(x) = \left\{        \begin{array}{ll}            cx^2+5x & \quad x

For the function f(x) to be continuous on (-\infty,\infty) it is sufficient to have continuity at x = 6, we need to ensure that as x approaches 6, the left and right limits match, this means that

\lim_{x \to 6^{-} } f(x)=\lim_{x \to 6^{+} } f(x)=f(x),

which holds if and only if

c\left(6\right)^2+5\left(6\right)=\left(6\right)^2-c\left(6\right)\\36c+30=36-6c\\42c=6

namely if c=\frac{1}{7}.

6 0
3 years ago
Find the value of<br> 3a²-4ab-26² when A= -1 and b-4
nata0808 [166]

Answer:

-657

Step-by-step explanation:

a= -1\\b= 4\\

Substituting the value of a and b

3a^{2}-4ab-26^{2}  \\3(-1)^{2} -4(-1)(4)-676\\3-4(-4)-676\\3+16-676\\19-676\\-657

The value of    3a²-4ab-26²  is -657

4 0
3 years ago
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