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Scilla [17]
3 years ago
12

Value of x...........in given rhombus. ​

Mathematics
2 answers:
Ann [662]3 years ago
8 0

Step-by-step explanation:

we know that,

《opposite angle are equal in a rhombus 》

HERE,

one angle =2x

Opposite angle =3x-40

<u>According</u><u> </u><u>to</u><u> </u><u>the question</u><u>, </u>

\tt{ 2x=3x-40  }

\tt{3x=2x+40   }

\tt{3x-2x=40   }

\tt{ x=40  }

<em>#quality</em><em> </em><em>answer</em><em> </em>

joja [24]3 years ago
3 0

\boxed{\large{\bold{\blue{ANSWER~:) }}}}

In this given rhombus,

  • one angle =2x°
  • another angle(opposite angle) =3x-40°

<u>we</u><u> </u><u>know that</u><u> </u>

\boxed{\sf{opposite~ angle~ are~ equal ~in~ a~ rhombus   }}

<u>According</u><u> </u><u>to</u><u> </u><u>the question</u><u>, </u>

  • one angle=opposite angle
  • 2x=3x-40
  • 2x-3x=-40
  • -x=-40
  • x=40°

<em><u>Therefore</u></em><em><u>. </u></em>

The value of x In the given rhombus is 40°

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