All categories

3 years ago

Value of x...........in given rhombus.

Mathematics

2 answers:

Ann [662]3 years ago

8 0

Step-by-step explanation:

we know that,

《opposite angle are equal in a rhombus 》

HERE,

one angle =2x

Opposite angle =3x-40

According to the question, 

$\tt{ 2x=3x-40 }$

$\tt{3x=2x+40 }$

$\tt{3x-2x=40 }$

$\tt{ x=40 }$

#quality answer

joja [24]3 years ago

3 0

$\boxed{\large{\bold{\blue{ANSWER~:) }}}}$

In this given rhombus,

one angle =2x°
another angle(opposite angle) =3x-40°

we know that 

$\boxed{\sf{opposite~ angle~ are~ equal ~in~ a~ rhombus }}$

According to the question, 

one angle=opposite angle
2x=3x-40
2x-3x=-40
-x=-40
x=40°

Therefore. 

The value of x In the given rhombus is 40°

You might be interested in

Which expression is equivalent to...? Screenshots attached. Please help! Thank you.

Studentka2010 [4]

Answer:

$4x^{3} y^{2} (\sqrt[3]{4 x y})$

Step-by-step explanation:

Another complex expression, let's simplify it step by step...

We'll start by re-writing 256 as 4^4

$\sqrt[3]{256 x^{10} y^{7} } = \sqrt[3]{4^{4} x^{10} y^{7} }$

Then we'll extract the 4 from the cubic root. We will then subtract 3 from the exponent (4) to get to a simple 4 inside, and a 4 outside.

$\sqrt[3]{4^{4} x^{10} y^{7} } = 4 \sqrt[3]{4 x^{10} y^{7} }$

Now, we have x^10, so if we divide the exponent by the root factor, we get 10/3 = 3 1/3, which means we will extract x^9 that will become x^3 outside and x will remain inside.

$4 \sqrt[3]{4 x^{10} y^{7} } = 4x^{3} \sqrt[3]{4 x y^{7} }$

For the y's we have y^7 inside the cubic root, that means the true exponent is y^(7/3)... so we can extract y^2 and 1 y will remain inside.

$4x^{3} \sqrt[3]{4 x y^{7} } = 4x^{3} y^{2} \sqrt[3]{4 x y}$

The answer is then:

$4x^{3} y^{2} \sqrt[3]{4 x y} = 4x^{3} y^{2} (\sqrt[3]{4 x y})$

4 0

3 years ago

Find the dimensions of a rectangle with an area of 100 square feet that has the minimum perimeter.

STatiana [176]

The polygon with the shortest perimeter for a given area is a regular polygon. The regular 4-sided polygon is the square.

The side length of the square with an area of 100 ft² is √(100 ft²) = 10 ft.

The rectangle with the minimum perimeter for an area of 100 ft² is 10 ft by 10 ft.

8 0

3 years ago

BRAINLIEST ASAP! PLEASE HELP ME :)

Drupady [299]

The answer is √91,10

6 0

3 years ago

Read 2 more answers

What is the greatest common factor of 63 and 96

katrin [286]

Answer: 3

Step by step explanation

3 0