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kozerog [31]
3 years ago
11

Thank you guys for following and please follow more it's my humble request​

Mathematics
1 answer:
Romashka-Z-Leto [24]3 years ago
8 0

Answer:

Ok, I will... :) And can you also mark me as brainliest....

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A manufacturer of running shoes knows that the average lifetime for a particular model of shoes is 15 months. Someone in the res
Alexus [3.1K]

Answer:

Step-by-step explanation:

Hello!

So you have a new type of shoe that lasts presumably longer than the ones that are on the market. So your study variable is:

X: "Lifetime of one shoe pair of the new model"

Applying CLT:

X[bar]≈N(μ;σ²/n)

Known values:

n= 30 shoe pairs

x[bar]: 17 months

S= 5.5 months

Since you have to prove whether the new shoes last more or less than the old ones your statistical hypothesis are:

H₀:μ=15

H₁:μ≠15

The significance level for the test is given: α: 0.05

Your critical region will be two-tailed:

Z_{\alpha /2} = Z_{0.025}= -1.96

Z_{1-\alpha /2} = Z_{0.975}= 1.96

So you'll reject the null Hypothesis if your calculated value is ≤-1.96 or if it is ≥1.96

Now you calculate your observed Z-value

Z=<u>x[bar]-μ</u> ⇒ Z=<u>    17-15     </u> = 1.99

     σ/√n              5.5/√30

Since this value is greater than the right critical value, i.e. Zobs(1.99)>1.96 you reject the null Hypothesis. So the average durability of the new shoe model is different than 15 months.

I hope you have a SUPER day!

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