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2 years ago

Find x & y so that quadrilateral is a parallelogram. (Look at image) please help!!

Mathematics

1 answer:

dybincka [34]2 years ago

4 0

Answer:

y = 2 and x = -3

Step-by-step explanation:

we know that opposite sides of a parallelogram are equal so

7y + 3 = 12y - 7

12y - 7y = 3 + 7

5y = 10

y = 10 / 5

y = 2

Now

-6x = -4x + 6

-6x + 4x = 6

-2x = 6

x = 6 / - 2

x = - 3

Hope it will help :)❤

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Find two numbers such that the sum of their squares is 100. The square of the larger number is equal to the sum of the product o

Shtirlitz [24]

Answer with Step-by-step explanation:

Let x and y are two numbers

According to question

$x^2+y^2=100$ ....(1)

Suppose x is larger than y

$x^2=x(4y+8x)$

$x=4y+8x$

$x-8x=4y$

$-7x=4y$

$y=-\frac{7}{4}x$

Substitute the value of y

$x^2+(-\frac{7}{4}x)^2=100$

$x^2+\frac{49}{16}x^2=100$

$\frac{16x^2+49x^2}{16}=100$

$\frac{65}{16}x^2=100$

$x^2=\frac{16\times 100}{65}$

$x=\sqrt{\frac{1600}{65}}=\frac{40}{\sqrt{65}}=\frac{40}{65}\sqrt{65}=\frac{8}{13}\sqrt{65}$

$y=-\frac{7}{4}\times \frac{8}{13}\sqrt{65}=-\frac{14}{13}\sqrt{65}$

3 0

2 years ago

Tell which property is represented 12•14=14•12

kakasveta [241]

Answer:Communative

Step-by-step explanation:

5 0

3 years ago

Solve for c: c - 12 = 3

vlabodo [156]

Steps to solve:

c - 12 = 3

~Add 12 to both sides

c = 15

Best of Luck!

8 0

3 years ago

Read 2 more answers

Please help! Brainliest and 5 star given

goldfiish [28.3K]

Answer:

for second question

first length is 9cm

Area=l*b

= 9cm *9cm

=81cm

then, For semicircle

radius is 9 cm

area= 1/2*9cm

now , area of two semi circle = 2*1/2*9

= 9 cm

now area of shaded = 81-9

=72

5 0

3 years ago

Is RATIONAL , IRRATIONAL,NON REAL NUMBERS <img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B27" id="TexFormula1" title=" \sqrt{

Tanya [424]

Answer:

It's irrational

Step-by-step explanation:

the square root of 27 is equal to:

$\sqrt{27} = \sqrt{3\cdot3\cdot3} = 3\sqrt{3}$

We know that $\sqrt{3}$ is an irrational number (but a real number), so $3\sqrt{3}$ is the same.

In case we need to prove that $\sqrt{3}$ is irrational, please leave a comment.

8 0

3 years ago

Read 2 more answers