Answer:
And if we use a sample level of n =2000 the margin of error would be higher as we can see here:
Step-by-step explanation:
Previous concepts
A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".
The margin of error is the range of values below and above the sample statistic in a confidence interval.
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
represent the sample mean for the sample
population mean (variable of interest)
represent the population standard deviation assumed
n represent the sample size (variable of interest)
Confidence =98% or 0.98
ME = 10 represent the margin of error desired
The margin of error is given by this formula:
(a)
And on this case we have that ME =10 and we are interested in order to find the value of n, if we solve n from equation (a) we got:
(b)
The critical value for 98% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.01;0;1)", and we got 
, replacing into formula (b) we got:
So the answer for this case would be n=13573 rounded up to the nearest integer
And if we use a sample level of n =2000 the margin of error would be higher as we can see here:
