Question

A study reported that finger rings increase the growth of bacteria on health-care workers’ hands. Research suggests that 31 percent of health-care workers who wear rings have bacteria on one or both hands, and 27 percent of health-care workers without rings have bacteria on one or both hands. Suppose that independent random samples of 100 health-care workers wearing rings and 100 health-care workers not wearing rings are selected. What is the standard deviation of the sampling distribution of the difference in the sample proportions (wear rings minus does not wear rings) of health-care workers having bacteria on one or both hands?

Answer 1

Answer:

C: square root 0.31 (0.69)/100 + 0.27(0.73) /100

Step-by-step explanation:

that's the answer I'm just to lazy to put the explanation but yeah, that's the answer